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States the negation of the statement ∀x ∃y (xy = 1) so that no negation precedes a quantifier.
Ans: The negation of the following statement is written as ~ [∀x ∃y (xy = 1)]. And
~[∀x ∃y (xy = 1)] = ∃x [~∃y (xy = 1)]
= ∃x ∀y [~(xy = 1)]
= ∃x ∀y (xy ≠ 1)
a ,b,c are complex numbers such that a/1-b=b/1-c=c-1-a=k.find the value of k
one half y minus 14
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