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States the negation of the statement ∀x ∃y (xy = 1) so that no negation precedes a quantifier.
Ans: The negation of the following statement is written as ~ [∀x ∃y (xy = 1)]. And
~[∀x ∃y (xy = 1)] = ∃x [~∃y (xy = 1)]
= ∃x ∀y [~(xy = 1)]
= ∃x ∀y (xy ≠ 1)
Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
For the initial value problem y' + 2y = 2 - e -4t , y(0) = 1 By using Euler's Method along with a step size of h = 0.1 to get approximate values of the solution at t = 0.1, 0
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I am here to tell you, Alex has a cold.
Calculate the Probability A bag contains 80 balls of such 20 are red, 25 are blue and 35 are white. A ball is picked at random what is the probability that the ball picked is
0.875 of a number is 2282. What is the number ?
Let the Sample Space S = {1, 2, 3, 4, 5, 6, 7, 8}. Suppose each outcome is equally likely. Compute the probability of event E = "an even number is selected".
If sin? = 1/2 , show that 3cos?-4cos 3 ? = 0. Ans: Sin ? = ½ ⇒ ? = 30 o Substituting in place of ? =30 o . We get 0.
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