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States the negation of the statement ∀x ∃y (xy = 1) so that no negation precedes a quantifier.
Ans: The negation of the following statement is written as ~ [∀x ∃y (xy = 1)]. And
~[∀x ∃y (xy = 1)] = ∃x [~∃y (xy = 1)]
= ∃x ∀y [~(xy = 1)]
= ∃x ∀y (xy ≠ 1)
Simultaneous equations by substitution: Solve the subsequent simultaneous equations by substitution. 3x + 4y = 6 5x + 3y = -1 Solution: Solve for x: 3x = 6
rouding each number to the nearest half
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5.02
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