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A particle moves along a straight line so that after t secs its distance from fixed point O on the line is given by s=(t-1)^2(t-2).find the distance from O when the velocity is zer
if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5 are in AP find x. 1/x+3 - 1/x+2 = 1/x+5-1/x+3 => 1/x 2 +5x+6 = 2/ x 2 +8x +15 => On solving we get x
tan 2x = 1
Derivative for Parametric Equations dx/dy = (dx/dt) / (dy/dt) , given dy/dt ≠ 0 Why would we wish to do this? Well, remind that in the arc length section of the Appl
?[1,99] x^5+2x^4+x^3+5x^2+6x+2÷x^2+2x
What percent of the figure below is shaded? Break the rectangle into eighths as shown below. The shaded part is 6/8 or 3/4; 3/4 is 75%.
what is 5x - 14x + 7x =
what help with trigonometry?
Patrick has a rectangular patio whose length is 5 m less than the diagonal and a width which is 7 m less than the diagonal. If the field of his patio is 195 m 2 , what is the lengt
I need help with my calculus work
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