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Can you give an example of when it would be appropriate to use a web service as opposed to a non-serviced .NET component?
Services which help in stock trading by giving analysis of market trends could best be executed as a web service. The reasons are
1. Such a web service would be simply discovered by potential customers when they need it.
2. It will need minimal setup on the client machines
3. The updates to the system will be automatically available to all its consumers, without any requirement to deploy the updates on their machines.
Explain the role of World Wide Web in the field of e-commerce. In the 1990s, the arrival of the World Wide Web on the Internet had shown a turning point in e-commerce by givin
Illustrate the benefits of Functional model Functional model shows how values are computed. This model describes decisions or object structure without regard for sequencing. I
Q. Explain about Zip Drive? Zip Drive: Loads of files, Volumes of data have definitely increased onus on today's computer user and protection of this data is what bugs every
Q. What is the impact of overflow for binary numbers? An overflow is said to have happened when sum of two n digits number takes n+ 1 digits. This definition is perfectly appli
Explain the action of an interrupt processing routine? Action of an interrupt processing routine is as follows : 1. Save contents of registers of CPU. This action is not e
Whenever we compile with -g option, it will make a symbol table, and according that table for every function and line it will call ptrace.
Explain R-2R ladder D/A converter. Ans. R-2R ladder D/A converter: An R-2R ladder D/A converter is shown in Fig.(a). It uses resistors of only two values R and 2R. The inp
Single Instruction and Single Data stream (SISD) In this organisation, sequential implementation of instructions is executed by one CPU having a single processing element (PE
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Prove the equations A + A‾ .B + A.B‾ = A + B using the Boolean algebraic theorems ? Ans. The equation is A + A‾.B + A.B‾ = A + B L.H.S. = A + A‾ .B + A.B‾ = (A + A.B‾) + A‾.B
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