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Type Casting
Implicit type conversions, as allowed by the language, can lead to errors creeping in the program if care is not taken. Thus, explicit type conversions may be used in mixed mode expressions. This is done by type-casting a value of a certain type, into the desired type. This is done by using the (type) operator as follows:
(type) expression
expression is changed to the given type by the rules stated above.
e.g.
float a = 10.0, b = 3.0, c;
c = a / b;
This expression will result in 3.333333 being stored in 'c'. If the application needs integer division of two floating point numbers, then the following expression with the type cast can be used:
c = (int)a / (int)b;
or
c = (int) (a / b);
how to make a program this struct items/product
Multidimensional Arrays - Every dimension is specified in separate brackets e.g. int arr[4][3]; This is a two-dimensional array with 4 as row dimension and 3 as
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Operation on array: void Array::add( Object& toAdd ) { lastElementIndex++; while( ptrAt( lastElementIndex ) != ZERO && lastElementIndex
Describe the “placement new" and why would I use it?
A: The answer to this lies actually, how they used. Along ++i(PreIncrement) the variable is incremented and new value is returned. Thus it needs one instruction to increment the va
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F u nction overloading: Functions can be defined with same name. Depending upon the type of argument passed the function will perform. This is known function overloading
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P r i va t e Member Functions: A private member functions can be called by the members of the same class. Consider the following example. c l a ss sample
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