Explain the Relational Operator Precedence ?

Whenever a new operator is introduced you have to ask yourself whereas it fits in the precedence tree. If you seem back at the instance in the last section, you'll remember in which it was implicitly supposed that the arithmetic was done before the comparison. Otherwise, for example

boolean test8 = 6*4 < 3*8; // False. 24 is not less than 24

4 < 3 returns false that would then be multiplied through six and eight that would generate a compile time error since you can't multiply booleans. Relational operators are evaluated after arithmetic operators and before the assignment operator. == and != have slightly lower precedences than <, >, <= and >=. Here's the revised order:

1. *, /, % Do all multiplications, divisions and remainders from left to right.
2. +, - Next do additions and subtractions from left to right.
3. <, >, >=, <= Then any comparisons for relative size.
4. ==, != Then do any comparisons for equality and inequality
5. = Finally assign the right-hand side to the left-hand side

For example,
boolean b1 = 7 > 3 == true;
boolean b2 = true == 7 > 3;
b = 7 > 3;