Explain the ray diagrams for mirrors, Physics

Assignment Help:

Explain the Ray Diagrams for Mirrors?

To figure out the position and size of an image reflected by a curved mirror, you can draw a scaled diagram of the mirror as follows: along the principle axis are the center of the radius of curvature of the mirror, C, and the focal point of the mirror, F, which is half-way between C and the mirror. The following diagram is for an object at a distance greater than 2r from a concave mirror.

1568_Ray Diagrams for Mirrors 1.png

Once you draw in the object, it is easy to draw three light rays in any ray diagram, as our diagram of a concave mirror shows:

     #1: a light ray parallel to the axis from the top of the object will reflect and be drawn from the surface of the mirror back through the focus, F.
    #2: a light ray drawn from the top of the object through F reflects off the mirror and can be drawn parallel to the principal axis.
    #3: a light ray can be drawn from the top of the object through the point C and the reflected ray will fall back along the same path.

    The image is where these three rays intersect. In this case, the image is smaller, inverted and situated between F and C, closer to F. If the drawing is done carefully to scale, the exact distance and height of the image can be measured from the diagram

442_Ray Diagrams for Mirrors 2.png

In the case of a convex mirror, the points C and F are behind the mirror and the three rays are drawn as follows:

    #1: Begin with a ray drawn from the top of the object to the mirror parallel to the central axis. If you drew a line (shown as a dotted line on our diagram) from point F through the point at which the ray hits the mirror, then the ray would be reflected back along the extension of the line.
    #2: Draw a light ray from the top of the object through the point C behind the mirror, and the reflected ray will fall back along the same path.
    #3: Draw a light ray drawn from the top of the object to the point F behind the mirror. The reflection is drawn parallel to the principal axis from where the incident ray intersects the mirror surface. It is useful to extend this reflected ray behind the mirror.

Where the three extended reflected rays intersect, there is the virtual image. The virtual image is an image that cannot be seen on a screen placed at this position, because the light only seems to be coming from behind the mirror, but does not actually go behind the mirror. In this case, the image is erect, smaller than the object and situated between F and the mirror, closer to F. If the drawing is done carefully to scale, the exact distances and heights of the image can be measured from the diagram.

The lens equation can be used for mirrors with a positive focal length for concave spherical mirrors and a negative focal length for convex spherical mirrors. (See the end of the Ray Diagrams lesson for the section on Thin Lenses.) All other sign conventions are the same as described for lenses.

A plane mirror is a perfectly flat mirror. The image can be determined with a ray diagram. The object is represented by the thick black arrow.

2341_Ray Diagrams for Mirrors 3.png

Two rays can be drawn from the top and the bottom of the arrow. The incident rays can be at 90o to the mirror and be reflected back on the same path (1). Alternatively, for rays that are not perpendicular, you can use the angle of incidence to figure the angle of reflection, because the angle of reflection relative to normal is equal to the angle of incidence (2). If you then extend the reflected rays along the angle of reflection back behind the plane mirror, the point where the two rays from the top of the object (1) intersect with the extended line of the angle of reflection (dotted line 2) is at a distance behind the mirror equal to the distance from the top of the object to the front of the mirror. The two rays reflected from the bottom of the object intersect at a distance behind the mirror equal to the distance from the bottom of the object to the front of the mirror. So, the image (represented by the dotted arrow) is the same size as the object. It is an erect, virtual image as far behind the mirror as the object is in front of the mirror. The image is laterally reversed.


Related Discussions:- Explain the ray diagrams for mirrors

Longitudinal waves and tuning forks, Longitudinal Waves and Tuning Forks ...

Longitudinal Waves and Tuning Forks Sound waves are generates through vibrating objects. Whether it is the sound of a person's voice, the sound of a piano and the sound of a tr

Problems regarding open organ pipes and closed organ pipes, a closed organ...

a closed organ pipe resonates with frequency 6hz and an open organ pipe resonates with frequency 12Hz. if the two organ pipes are joined to form a single organ pipe then it will re

State parallelogram law of forces, State parallelogram law of forces. P...

State parallelogram law of forces. Parallelogram Law can be assured as if two forces acting at a point are represented in magnitude and direction by the adjacent sides of a par

Estimate ground level no concentration, A stack emitting 85 g/s of NO has a...

A stack emitting 85 g/s of NO has an effective stack height of 100 m. The wind speed is 3 m/s at 10 m, and it is a cloudy summer day.  Estimate ground level NO concentration:

What are the magnitude and the direction of rider velocity, A park ride is ...

A park ride is designed so that the rider is on the edge of a revolving platform, 3.5 m from the platform's center. This platform is mounted 8.0 m from the center of a larger revol

Conservation of energy, CONSERVATION OF ENERGY 1.   Potential energy ...

CONSERVATION OF ENERGY 1.   Potential energy is, as the word suggests, the energy "locked up" up somewhere and which can perform work. Potential energy Potential energy can b

Correspondence limit, Correspondence limit (N. Bohr) The restriction at...

Correspondence limit (N. Bohr) The restriction at which a more general theory decrease to a more specialized theory while the conditions that the specialized theory needs are t

#title, Ask questiA 1.10×10-2-kg bullet strikes a 0.300-kg block attached t...

Ask questiA 1.10×10-2-kg bullet strikes a 0.300-kg block attached to a fixed horizontal spring whose spring constant is 2100 N/m and sets it into oscillation with an amplitude of 1

The water will not spill, The water will not spill Get a small pail and...

The water will not spill Get a small pail and fill it nearly full with water . Swing it around rapidly at arms' length and the water will not spill because of centrifugal force

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd