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Q. Explain the odd-even transposition algorithm?
The algorithm needs one 'for loop' beginning from I=1 to N it implies that N times and for every value of I, one 'for loop' of J is executed concurrently. So the time complexity of the algorithm is O(n) because there are total n phases and every phase executes either even or odd transposition in O(1) time.
Figure: Example
In a report with an LDB attribute, you do not have to explain how the information should be retrieved from the database tables, but only how the data should be shown on the screen.
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