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Q. Explain the odd-even transposition algorithm?
The algorithm needs one 'for loop' beginning from I=1 to N it implies that N times and for every value of I, one 'for loop' of J is executed concurrently. So the time complexity of the algorithm is O(n) because there are total n phases and every phase executes either even or odd transposition in O(1) time.
Figure: Example
A 2-digit BCD D/A converter is a weighted resistor type with E R = 1 Volt, with R = 1M? , R f = 10K? . Find resolution in Percent and Volts. Ans. Resolution = 1/2 2 = 0.25 vo
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REPRESENTATION OF POYNOMIAL OF 2 OR MORE VARIABLES USING ARRAY
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Determine the advantages of BCD Adder Now let us see the arithmetic addition of two decimal digits in the BCD, with a possible carry from previous stage. As each input digit do
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