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Q. Explain the odd-even transposition algorithm?
The algorithm needs one 'for loop' beginning from I=1 to N it implies that N times and for every value of I, one 'for loop' of J is executed concurrently. So the time complexity of the algorithm is O(n) because there are total n phases and every phase executes either even or odd transposition in O(1) time.
Figure: Example
Q. Describe about general-purpose registers? The general-purpose registers as the name proposes can be used for several functions. For illustration they may comprise operands o
Use tabs to bring some structure into your function body if(nPos > 1) then nRetrun = True else nRetrun = False end if
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Q. Define about EXE Programs? An EXE program is stored on disk with extension .exe. EXE programs are longer than COM programs as every EXE program is related with an EXE header
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Demonstrate how a typical DMA controller can be interfaced to an 8086/8085 based maximum mode system. For 8088 in maximum mode: The RQ/GT0 and RQ/GT1 pins are used to is
8085 the interrupts are classified as Software and Hardware interrupts.
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