Explain the method of overlapping and intersecting, Data Structure & Algorithms

Assignment Help:

Overlapping or Intersecting

A polygon overlaps or intersects the current background if any of its sides cuts the edges of the viewport as depicted at the top right corner of the viewport.

The extent of a polygon overlapping the viewport is only a necessary but not sufficient condition, because even if the extent overlaps, the polygon may be disjoint, as illustrated at the top left corner of the viewport. It may be seen that only the surrounding and contained cases (a) and (b) may be decided on the basis of the simple rules of relationship between the x-y extents of the polygon and the viewport. All other cases need further investigation, as follows : 

We start with the entire viewport, and examine all the polygons for surrounding or containment. Whatever polygons can be classified as Case (a) or Case (b) can be stored or not depending on whether they are visible or not.

For any remaining polygons, the viewport is divided into four quarters, and each quarter representing a viewport segment is evaluated against the polygon portions in that quarter for cases (a) and (b). The quarter or quarters in which such determination cannot be made will again be subdivided into four further quarters each, and each quarter (which may be termed a "viewport segment") examined for the same kind of relationship decisions.

This procedure is applied with successive subdivisions until all the polygons and sub-regions can be resolved as (a) or (b). Frequently, the procedure may have to be repeated until the last quartering reduces to a single pixel. Because of the four branches formed with each quartering step, the method is also called the Quad tree method. Finally, the method illustrates the difference between hidden-line and hidden-surface algorithms. In a particular viewport segment, it may happen that there are no edges at all, but two or more surfaces are surrounding the viewport segment. Here, hidden line has no relevance, but hidden surface has. 

 


Related Discussions:- Explain the method of overlapping and intersecting

Structure of an avl tree, Given is the structure of an AVL tree: struct ...

Given is the structure of an AVL tree: struct avl { struct node *left; int info; int bf; struct node *right; }; 2) A multiway tree of n order is an ord

Big o notation, This notation gives an upper bound for a function to within...

This notation gives an upper bound for a function to within a constant factor. Given Figure illustrates the plot of f(n) = O(g(n)) depend on big O notation. We write f(n) = O(g(n))

Define the terms - key attribute and value set, Define the terms   ...

Define the terms     i) Key attribute     ii) Value set  Key attribute:  An entity  type  usually  has  an attribute  whose  values  are  distinct  fr

Trees, What is AVL Tree? Describe the method of Deletion of a node from and...

What is AVL Tree? Describe the method of Deletion of a node from and AVL Tree ?

Binary search tree bst, Describe Binary Search Tree (BST)? Make a BST for t...

Describe Binary Search Tree (BST)? Make a BST for the given sequence of numbers. 45, 36, 76, 23, 89, 115, 98, 39, 41, 56, 69, 48 Traverse the obtained tree in Preorder, Inord

Project, human resource management project work in c++

human resource management project work in c++

Quick sort, This is the most extensively used internal sorting algorithm. I...

This is the most extensively used internal sorting algorithm. In its fundamental form, it was invented by C.A.R. Hoare in the year of 1960. Its popularity lies in the easiness of i

Which is the most suitable data type, Problem 1. You are asked to store...

Problem 1. You are asked to store Names of all 100 students of class A in your Learning Centre. Which data type will you use? What is its syntax? Explaining the data typ

Illustrate the intervals in mathematics, Illustrate the intervals in mathem...

Illustrate the intervals in mathematics Carrier set of a Range of T is the set of all sets of values v ∈ T such that for some start value s ∈ T and end value e ∈ T, either s ≤

Splaying steps - splay trees, Readjusting for tree modification calls for r...

Readjusting for tree modification calls for rotations in the binary search tree. Single rotations are possible in the left or right direction for moving a node to the root position

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd