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Explain the Design Procedure for Flip Flop?
The design procedure as follows.
1) Acquire the clear description of the desired flip flop X.2) Acquire the present state- next state table for the desired flip flop.3) Using the excitation table of the chosen flip flop Y append the next state code to the above tale.4) Using K map simplift the logical expression for the excitation inputs of flip flop Y.5) Draw the circuit for the desired flip flop X.
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I think yes...so if 8259 gives interrupt then it will be serviced instantly but since into pin is left hanging the insr bit will never be set...and so whenever any interrupt occurs
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