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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
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How can I handle a destructor that fails? Need help please provide example also.
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I have a Matlab assignment and I have the assignment description+ algorithm + and the output sample. the files are on a dropbox folder and you can download them from the link below
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Returning References from Functions Just as in passing the parameters by reference, returning a reference also doesn't return back a copy of the variable , instead an alias is
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