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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
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WAP TO PRINT NUMBERS FROM 1-50 WHICH ARE DIVIDED BY 7 void main () { int a; clrscr (); a=1; while (a { if (a%7==0) printf ("%d\n",a); a++; } ge
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how many types of class relationship
I need to implement a mini version of linux''s ''tar'' function in C.
area
Write a program to calculate the average of ten numbers #include stdio.h /* Only this header is needed since only IO are used */ void main() { char
C Program for REMOVING CHAR WHICH U WANT void main() { int i,j; char a[100],r; clrscr(); for(i=0;i
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