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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
plaese tell the full program for the above given topic with the input and output
HOW CAN WE EASLY LEARN C++
What is Ms dos?
6999066263304447777077766622337778 -----> message sent by the first smuggler. my name is robert---------> message decoded by the second smuggler. Where ‘0’ denotes the "space".
idiet manaagement
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A: Provided that function parameter is "const reference", compiler create temporary variable in following two ways. a) The actual argument is the correct type, however it isn't
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