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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
#include "stdafx.h" #include iostream using namespace std; int _tmain(int argc, _TCHAR* argv[]) { int NumbHold[5]; int * ptrNumb;
Run the following C++ program with and without preprocessor variable POSTFIX defined. #include using namespace std; extern "C" int atoi( const char *str );
Of course it is C[i] = A[i] + B[i].It was a typing mistake,never mind. You just understand the concept. 27-1 b. for grain-size=1 n=A.length grain-size=1 r=n for
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