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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
The following is the formula that can be used to complete that calculation: Monthly Payment = Monthly Interest Rate / (1 - (1 + Monthly Interest Rate) -Payment Interval )) *
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pebble merchant codings in c++
Should I call a destructor explicitly on a local variable?
a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between tw
#questiStarting with a blank solution, write a program to prompt the user for an employee number, hourly rate and hours worked. Compute and display the employee number, gross weekl
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TO CONVERT A NUMBER OR A DIGIT INTO ALPHABET
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