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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
#include #include #include #include #include class Employee { private: char *Name; //Set them as pointers... int IdNumber; char *Department; char *Position; public: voi
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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
how to create a shopping cart and sibmit the code segment on screan
pls help me to decode this.
Define a structure of student class: Write a program to define a structure of student record in C. class student { char name[20]; int roll_no; int marks[2];
#write a program that counts the number of occurances of the string in the n-th padovan string p(n)
Q-What happens while a function throws an exception which was not specified through an exception specification for this function? A: Unexpected() is called, which, by default, w
C Program to check FACTORIAL main() { int i,j,m,fact,sum=0; clrscr(); printf("ENTER THE NO.: "); scanf("%d",&m);
program to find if a no . is prime or not
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