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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
Relationship between an Array and Pointers. Consider the following. int arr[] = {0,1,2,3,4,5,6,7,8,9}; If we write arr , it is considered as the address of the first elem
By pressing ‘6’ (i.e. key’6’ one time) on the keypad, the mobile shows ‘m’ on display screen in write text message area
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write a c++ program for the sum of 10 numbers and print out the average
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A: No. If they're utilized properly, they increase encapsulation. You frequently require splitting a class in half while the two halves will have distinct numbers of instances o
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