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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
WAP TO SWAP THE THREE DIGIT NUMBER void main () { int b,r,n,r1,r2; clrscr (); printf ("Enter the Value: "); scanf ("%d",&n); r=n%10; n=n/10; r1=n%10;
program
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A: Use operator overloading to present a friend right-shift operator, operator>>. It is similar to the output operator, except the parameter doesn't contain a const: "Fred&" instea
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