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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
I need the code for this plss....
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A: The inline keyword tells the compiler to substitute the code in the function de_nition for each instance of a function call. Though, substitution takes place only at the compile
1 Aims The main purpose of the assignment is to let you practice the following programming techniques: perform operations on pointers to basic and more complex types;
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