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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
c | c-c-c-c-c | c-c-C-c-c | c find distance between difftent carbon atom by programing
3 . Write a ‘C’ program to accept any 3 digit integer number from the keyboard and display the word equivalent representation of the given number.
Program to check even and odd numbers: int main() { int your_number; cout cin >> your_number;
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What happens if you write following code? string& foo()
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