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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. #include float start
It tells the compiler that a variable or a function exists, even if the compiler hasn't yet seen it in the file presently being compiled. This variable or function may be distinct
Is there any difficulty with the following : char*a=NULL; char& p = *a;? A: The result is indeterminate. You must never do this. A reference has to always refer to some object.
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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
Force, F = ma
Rules of function: Inline function created without prototype it reduces the memory and it is used only for small function. Inline function cannot have recursion, static var
Smugglers are becoming very smart day by day. Now they have developed a new technique of sending their messages from one smuggler to another. In their new technology, they are send
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