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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
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Q: How the compiler arranges the several sections in the executable image? A: The executable contained following sections: 1. Data Section (initialized data variable sec
how c program starts executing?
When I develop a destructor, do I require to explicitly call the destructors for my member objects?
A: Use operator overloading to present a friend right-shift operator, operator>>. It is similar to the output operator, except the parameter doesn't contain a const: "Fred&" instea
Write a program that finds the minimum total number of shelves, including the initial one required for this loading process.
lcm program.
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