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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
The Main program is slightly more complicated and you need to think about the I/O process. First of all, for most applications you do not call the low level routines GetChar and P
Write a program to calculate e^x using the formula: e^x = 1 + x/1! + x^2/2! + x^3/3! + ...... Allow the user to enter the integer number x, then do the calculation in a loop (for
Define conversion constructor?
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Write a Program to illustrate the Call by Reference? Here is an illustration: #include . int compute_sum(int *n); int main( void) { int n=3, sum; printf("%d\n",n); /
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write c++ program to decode the given code. in mobile keypad the integers from 1 to 9 will display the characters from a to z and 0 will assign a space
i need the program related to the topic
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