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Show that for odd positive integer to be a perfect square, it should be of the form
8k +1. Let a=2m+1
Ans: Squaring both sides we get a2 = 4m (m +1) + 1
∴ product of two consecutive numbers is always even
m(m+1)=2k
a2=4(2k)+1 a2 = 8 k + 1
Hence proved
For a first order linear differential equation the solution process is as given below: 1. Place the differential equation in the correct initial form, (1). 2. Determine the i
marketing plan for new product
76 is 2% of what number?
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t=w,w 2 L.H.S (w+w 2 ) + (w 2 + w) 2 ........ 1 + 1 ..... But every third term is of the form: (w 3n +w 3n ) 2 =22 There are nine such terms. Their sum is 36. The rema
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