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Q. Explain Source encoding or data compression?
The sequence of binary digits from the source encoder, known as the information sequence, is passed on to the channel encoder. The purpose of the channel encoder is to introduce some redundancy in a controlled manner in the binary information sequence, so that the redundancy can be used at the receiver to overcome the effects of noise and interference encountered in the transmission of the signal through the channel. Thus, redundancy in the information sequence helps the receiver in decoding the desired information sequence, thereby increasing the reliability of the received data and improving the fidelity of the received signal.
The binary sequence at the output of the channel encoder is passed on to the digitalmodulator, which functions as the interface to the communication channel. The primary purpose of the digital modulator is to map the binary information sequence into signal waveforms, since nearly all the communication channels used in practice are capable of transmitting electric signals (waveforms). Because themessage has only two amplitudes in a binary system, themodulation process is known as keying. In amplitude-shift keying (ASK), a carrier's amplitude is shifted or keyed between two levels. Phase-shift keying (PSK) involves keying between two phase angles of the carrier,whereas frequency-shift keying (FSK) consists of shifting a carrier's frequency between two values.Many other forms of modulation are also possible.
Q. Draw and explain an RC integrator, with equations RC Integrator is a low pass RC circuit in which the output is taken across capacitor. The low pass RC circuit gives conside
Masking As we know the MASJ is used to cover some part of our face which we want to hide and to show other part of the face which we want to show. Similarly the
Relays a) Sketch the schematic symbol for a relay with a single pole changeover switch b) Determine the coil resistance and determine the current at 12Vdc c) Connect the r
discussion for experiment
Q. Write notes on clamping ? When a signal drives an open-ended capacitor the average voltage level on the output terminal of the capacitor is determined by the initial charge
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if a resistor present in the middle of two branches in such a way that their polarities coincide then how do we choose the polarity of that resistor
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