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Explain segmentation?
Segment memory addressing divides memory into many segments. Each of these segments can be considered as a linear memory space. Every one of these segment is addressed by a segment register.
Though since the segment register is 16 bit wide and memory needs 20 bits for an address the 8086 appends four bits segment register to attain the segment address. Hence to address the segment 10000H by, say SS register, the SS should contain 1000H.
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Which of the memories stores the most number of bits ? Ans. most number of bits stores in 32M x 8 As 2 5 x 2 20 = 2 25 Therefore 1M = 2 20 = 1K x 1K = 2 10 x 2 10
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Q. Compute Physical address of data byte? Offset of data byte = 0020h Value of data segment register (DS) = 3000h Physical address of data byte This computation
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