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Explain segmentation?
Segment memory addressing divides memory into many segments. Each of these segments can be considered as a linear memory space. Every one of these segment is addressed by a segment register.
Though since the segment register is 16 bit wide and memory needs 20 bits for an address the 8086 appends four bits segment register to attain the segment address. Hence to address the segment 10000H by, say SS register, the SS should contain 1000H.
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The 68HC11 series is based on the Motorola 6800/1 programming instruction set and hence is a fairly simple 8 bit microprocessor. The internal structure of the 6800/1 is shown below
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Q. How to calculate register indirect addressing? The effective address of operand in this technique is calculated as: EA= (R) and D = (EA) Address capability of regi
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