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Q. Explain Register Indirect Addressing?
In this addressing technique the operand is data in memory pointed to by a register. Or we can say in other words that the operand field specifies a register whichcomprises the address of operand which is stored in memory. This is almost similar to indirect addressing scheme except it is much faster than indirect addressing which requires two memory accesses.
Figure: Register Indirect Addressing
What are the Cycle based simulators Cycle based simulators are more like a high speed electric carving knife in comparison since they focus on a subset of the biggest problem:
When the get cursor command used in interactive lists? If the hidden information is not enough to uniquely recognize the selected line, the command GET CURSOR is used. The GET
The field SY-STEPL refers to The index of the screen table row that is presently being processed. The system variable SY-stepl only has a meaning within the confines of LOOP.
Q. Efficiency - Metrics for performance evaluation? The other significant metric employed for performance measurement is efficiency of parallel computer system it implies that
Directed-Test Methodology Building a directed verification environment with a comprehensive set of directed tests is very time-consuming and difficult. As directed tests only c
Signalling transfer point (STP) exist in (A) Strowger exchange (B) SS7 (C) Local area network (D) PABX Ans: STP that is stand f
A PCM system uses 8 bits per sample and the analog signal is limited to 4.3 kHz. The PCM data is transmitted using (a) BFSK and (b) ASK. Determine the bandwidth required for transm
One can change an infix expression to a postfix expression using a By using Stack you can convert infix expression to a postfix expression
Q. Logic diagrams for same Boolean expression? The expression F can be simplified using Boolean algebra. The logic diagram of simplified expression is drawn in fig (b)
Prove the following identities a. A ‾B ‾C‾ + A ‾BC ‾ + AB ‾C ‾ + ABC ‾ = C ‾ b. AB + ABC + A ‾ B + AB ‾C = B + AC Ans. a. LHS = A'B'C' + A'BC' + AB'C' + ABC' =
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