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The energy possessed by a object by virtue of its position or its configuration is called its potential energy.
Concept of potential energy is valid only in conservative field. In conservative force field when a object moves on a round trip then its kinetic energy will not change. But if we assume a point B on the path, then at point B, its kinetic power will not be equivalent as at point A. (Let K.EB < K.EA), we may say that this changes in kinetic energy has stored in configuration of system and this kept energy is known as potential energy of system
Field system: The object of the field system is to make a uniform magnetic field, within which the armature rotates. It consists of four parts- yoke, pole core, pole shoe and fiel
Total height of the gymnast just before falling back down is=(2+.3)=2.3m Energy gained at that point = m*g*h(m=mass, g=gravitational force, h=height) =55*9.8*2.3=1239.7 J
The magnifying power of an astronomical telescope in the normal adjustment position is 100. The distance among the objective and the eye-piece is 101 cm. Measure the focal lengths
What is cavitationin terms of ultrasonic? Cavitation is an effect which is generated into liquids by intensive ultrasonic waves. The resulting pressure waves make vacuum bubb
Demonstrate resonance and forced vibrations Consider four simple pendulums P,Q,R and S suspended from horizontal stretched rubber card AB. Let the lengths of pendulums p and R
a) Three charges, every equal to 1 micro coulomb, are placed at the three corners of a square of side 1 m. Find the electric field at the fourth corner. b) Determine the electri
Q. A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12 cm from P. At what point does the beam converge if the lens is (a)a convex len
Example of Ohm Law Now that we know how to draw a circuit, let's figure out what is happening in a simple one resistor, one battery (voltage source) circuit. Example 1 - H
Assumptions: Kinetic Energy=KE, Potential Energy=PE m=mass of the skateboarder=55 kg, Velocity v=1.80m/s So ,Initial Energy(KE) of the skateboarder=mv 2 /2 = 0.5* 55 * (1.8)^
dimension of units
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