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POLYNOMIALS: It is not once nor twice but times without number that the same ideas make their appearance in the world.
1. Find the value for K for which x4 + 10x3 + 25x2 + 15x + K exactly divisible by x + 7.
Ans: Let P(x) = x4 + 10x4 + 25x2 + 15x + K and g(x) = x + 7
Since P(x) exactly divisible by g(x)
∴ r (x) = 0
(Ans : K= - 91)
now
x4 + 7 x3
-------------
3x3 + 25 x2
3x3 + 21x2
-------------------
4x2 + 15 x
4x2 + 28x
-----------------
-13x + K
- 13x - 91
----------------
K + 91
∴ K + 91 = 0
K= -91
sin (5pi/12)
25/5(2+3)
265 divided by 7
If a school has lockers with 50 numbers on each combination lock, how many possible combinations using three numbers are there.
a) Using Karnaugh map, show X': A'BC'D'+ ABC'D'+ A'BCD'+ ABCD' (b) If R is an equival
http://www.idea.wsu.edu/Range/
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