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Explain Optimal Binary Search Trees
One of the principal application of Binary Search Tree is to execute the operation of searching. If probabilities of searching for elements of a set are called, it is natural to pose a question about an optimal binary search tree for which the average number of comparisons in a search is the smallest possible.
In the earlier unit, we have discussed about the arrays. Arrays are data structures of fixed size. Insertion & deletion involves reshuffling of array elements. Thus, arraymanipulat
What do you understand by tree traversal? The algorithm walks by the tree data structure and performs some computation at everynode in the tree. This process of walking by the
Hubs - In reality a multiport repeater - Connects stations in a physical star topology - As well may create multiple levels of hierarchy to remove length limitation of 10
The structures of files vary from operating system to operating system. In this unit, we will discuss the fundamentals of file structures with the generic file organisations. A
In this example, suppose the statements are simple unless illustrious otherwise. if-then-else statements if (cond) { sequence of statements 1 } else { sequence of st
For preorder traversal, in the worst case, the stack will rise to size n/2, where n refer to number of nodes in the tree. Another method of traversing binary tree non-recursively t
State the range of operation of ADT Operations of the Range of T ADT includes following, where a, b ∈ T and r and s are values of Range of T: a...b-returns a range value (an
Warnock's Algorithm An interesting approach to the hidden-surface problem was presented by Warnock. His method does not try to decide exactly what is happening in the scene but
(a) Suppose that t is a binary tree of integers (that is, an object of type BinTree of Int.) in the state shown in Figure 3. Give the vectors returned by each of the f
Q. Make the 11 item hash table resulting from hashing the given keys: 12, 44, 13, 88, 23, 94, 11, 39, 20, 16 and 5 by making use of the hash function h(i) = (2i+5) mod 11.
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