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Q. Explain Molarity and Replacement Reactions?
Ans.
Frequently in the chemistry lab we are confronted with situations where we are interested in the yield of a certain reaction but the reaction is not a simple mass-mass reaction. We must figure out some way around the problem.
Remember that in order to do any sort of stoichiometry you must
a) have a balanced chemical reaction and b) you must convert to moles before applying your reaction ratios.
In these problems, you are given the volume of one of the reactants and the molarity. You are going to need to convert the volume into moles using the definition of molarity (M). (Molarity is moles per liter of solution.)
The calculation should look something like this:
how to calculate equivalent weight of LMnO4
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