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Q. Explain Inductorless Filters
Inductorless (Active) Filters
Filters (used to pass or eliminate certain frequency components of a signal) that are suitable for IC fabrication, but which do not contain inductors, are known as active filters. They have the op amp as a common component. Figure 5.4.13 shows the basic op-amp circuit with frequency-dependent impedances. The voltage gain or voltage transfer function of this circuit is given by
with Zi = Ri and Zf = Rf (1/j ωCf ) (i.e., Rf and Cf in parallel). We have a low-pass filter with
is sketched in Figure 5.4.14, from which one can see that at the half-power or 3-dB point of fl, the dc value Rf /Ri goes down by a factor of 1/ √ 2 or 0.707. With Zf = Rf and Zi = Ri + 1/j ωCi (i.e., Ri and Ci in series), we have a high-pass filter for which we obtain
Explain Medium length lines? Medium length lines cover lines in the range of 50 to 150 miles (80 to 240 km). Due to the increased length of the line, the shunt capacitance of t
main differnce of frequence analysi method
Preventive and Regular Maintenance Preventive and regular manages of components of the distributions system is necessary to reduce/eliminate breakdowns. Care should be taken t
Basic Operations of 8085 Microprocessor The 8085 microprocessor performs followings five basic operations . 1. Opcode Fetch : Reading and decoding operation code of
List the operation modes of 8255 a) I.O Mode i. Mode 0-Simple Input/Output. ii. Mode 1-Strobed Input/Output (Handshake mode) iii. Mode 2-Strobed bidirectional mode
Schottky diodes The schottky diodes have very fast recovery time and low forward drop. The current ratings of these diodes vary from 1A to 300 a and maximum allowable
Q. If an antenna has an available noise power of 1.6 × 10 -15 W in a 1-MHz bandwidth, find the antenna temperature.
Dielectric materials are (A) Insulating materials. (B) Semiconducting materials. (C) Magnetic materials. (D) Ferroelectric materials. Ans:
Define Cables - Generation and Absorption of Reactive Power? It is well known that the shunt capacitance of the cable is very large as compared to that of an overhead line. Thi
if a resistor is present between 2 branches in such way that its polarities are different to compare with one another so how we choose polarity of that resistor
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