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General graph directory
The serious problem with using an acyclic-graph structure is ensuring that there are no cycles. When we insert links to an existing tree-structured directory, the tree structure is damaged, resulting in a simple graph structure.
If cycles are permitted to exist in the directory, we likewise require to avoid searching any component twice, for reasons of correctness as well as performance.
ADVANTAGES AND INCONVENIENCES OF KLT Advantages: the kernel be able to simultaneously schedule many threads of the same process on many processors blocking
What are the different types of semaphore? Principally the semaphore is able to be classified into two on the basis of their values a) Counting semaphore: In counting s
Q. Is there any way to execute truly stable storage? Describe your answer. Answer: Truly steady storage would never lose data. The fundamental technique for steady storage is
The following is a dump of a TCP header in hexadecimal format: 00CD0018 00000EF1 00000D5D 502200D1 01BF0010 We need to first split the above hex as such 00 CD 00 18 00 00
Question: a) Each process is represented in the operating system by a process control block (PCB). The PCB contains many pieces of information associated with a specific proce
What are the different files attributes? File name:-it's the name of the file. It's the name with which the user identifies. Identifiers:-it's created when a file is created
Q. Consider the following page-replacement algorithms. Rank the algorithms on a five-point scale from "bad" to "perfect" according to their page-fault rate. Detach those algorithm
Why is rotational latency usually not considered in disk scheduling? How would you modify SSTF, SCAN, and C-SCAN to include latency optimization? Most disks do not export their
What is Demand paging? Virtual memory is commonly executed by demand paging. In demand paging, the pager brings only those essential pages into memory instead of swapping in a
Internal file structure All disk I/O is performed in units of single block, and all blocks are the similar size. It is unlikely that the physical record size will exactly match
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