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Consider the following example:
int max(int x, int y)
{
return ( x > y) ? x : y ;
}
float max(float x, float y)
long max( long x, long y)
char max(char x, char y)
void main()
cout << max( 1,2) << endl;
cout << max( 4L,3L) << endl;
cout << max( 5.62,3.48) << endl;
cout << max('A','a') << endl;
The output is :
2
4
5.62
a
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#questioA Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a str
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