Explain friend for overloading operators, C/C++ Programming

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Friend for Overloading Operators

Sometimes friend functions cannot be avoided. For example with the operator overloading. Consider the following class that have data members to simulate a matrix. Several operations can be performed on the matrices. One of them is to multiply the given matrix by a number (constant literal). There are two ways in which we can do this. The two ways are:

                Matrix * num;

 

   [or]

num * Matrix;

In the first case we can overload * to perform the operation and an object invokes this as the statement gets changed to :

Mobj.operator*(num);

Where Mobj is an object of Matrix and num is a normal integer variable. What happens to the second one ? It  gets changed by the compiler as :

num.operator*(Mobj);

Let us see this program in detail.

class Matrix

{

  public:

:

                                :

                                Matrix &operator*(int num);

                                friend Matrix &operator*(int n, Matrix &m);

 private:

                                int mat[20][20];

                                int rows, cols;

}

 

Matrix Matrix::operator*(int num)

 {

  Matrix temp;

  temp.rows=rows;

  temp.cols=cols;

 

   for(int i=1; i<=rows; i++)

                for(int j=1; j<=cols; j++)

                                temp.mat[i][j]=mat[i][j]*num;

    return (temp);

 

 }

 

Matrix operator*(int n, Matrix &m)

{

   Matrix temp;

 

                temp= m*n;

                return temp;

}

 

void main()

 {

Matrix M1, M2, M3;

int num;

  :

  :                             // accept matrix one and num

 

M2=M1*num;  // calls member operator function.

M3=num*M1;  // calls friend function.

 }

 


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