Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Explain FDM and show how CCITT standards help in building the base band?
Frequency Division Multiplexing: This is the process of combining some information channels through shifting their signals to various frequency groups in the spectrum therefore they can be transmitted simultaneously over common transmission service.
The bandwidth of a telephone speech signal is quite less than 4 kHz. Where, the available bandwidth on unloaded cables pair is fine above 100 kHz. Therefore this is possible, by using modulation techniques, for divide up the cable bandwidth then a number of telephone speech paths can be carried at the same time along a single cable pair. The normal arrangement contains 24 telephone channels per cable pair, the modulation in 24 channels being carried out within the two stages. In the primary stage, 12 channels are multiplexed together to form that is commonly termed as a basic group. This basic group arrangement is demonstrated in figure. Each of the 12 telephone signals are single side-band amplitude modulated on to carriers spaced at 4 kHz intervals 64 kHz to 108 kHz. The lower side-band (LSB) is utilized in every case. The 12 base-band signals are thus translated in the frequency band from 60 kHz 108 kHz as demonstrated. The block diagram for the channel translating equipment is specified in figure. To form a 24-channel system, to basic groups are occupied together. One basic group (B) is transmitted directly as this stands. Another basic group (A) is amplitude modulated on to a carrier are 120 kHz and the lower side-band is occupied such as to take the frequency range from 12 kHz to 60 kHz as demonstrated in figure. by using two stages of modulation for basic group A, this is possible to decrease the physical size of the component needed for the LSB filters of the figure, because the lowest cut- off frequency needed is at 64 kHz quite than 12 kHz when the whole block of 24 channels were assembled together in one stage of modulation.
FIG - Basic Group Arrangement
FIG - Channel Translating Equipment
? Actor: Actor shows an external user / end user who interact with the system. ? Object: Object is shown by one of components of the system. ? Unit: A unit is a subsystem, o
Convenience of Environments -artificial intelligence: In some cases, some aspects of an environment which should be taken into account in decisions about actions may be unavai
Does it makes sense for two domain servers to contain exactly the same set of names? Why or why not? Yes. This is very advantageous for 2-domain servers having same set of name
Q. When an object travels with constant velocity does its average velocity during any time interval differ from its instantaneous velocity at any instant? Answer:- No It i
Q. Evaluate Physical address of top of stack? Value of stack segment register (SS) = 6000h Value of stack pointer (SP) which is Offset = 0010h So Physical address of top
Write a Verilog code for synchronous and asynchronous reset? Synchronous reset, synchronous means clock dependent so reset must not be present in sensitivity disk eg: alway
what is software engineering?
A protocol is a formal description of message formats and the rules two or more machines must follow to exchange those messages. Because TCP (transmission control protocol) and IP
What is roll area? A roll area having the program's runtime context. In addition to the runtime stack and other structures, all local variables and any data known to the prog
What is WMFC
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd