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Depth-first traversal
A depth-first traversal of a tree visit a node and then recursively visits the subtrees of that node. Likewise, depth-first traversal of a graph visits a vertex and then recursively visits all the vertices adjacent to that node. The catch is that the graph may having cycles, but the traversal must visit each vertex at most once. The solution to the problem is to keep track of the nodes that have been visited, so that the traversal does not undergo the fate of infinite recursion.
Determine the importance of array Arrays are significant since they allow many values to be stored in a single data structure whereas providing very fast access to each value.
There are four data type groups: Integer kepts whole numbers and signed numbers Floating-point Stores real numbers (fractional values). Perfect for storing bank deposit
Determine the greatest common divisor (GCD) of two integers, m & n. The algorithm for GCD might be defined as follows: While m is greater than zero: If n is greater than m, s
Q. The given values are to be stored in a hash table 25, 42, 96, 101, 102, 162, 197 Explain how the values are hashed by using division technique of hashing with a table
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
algorithm for insertion in a queue using pointers
Build a class ?Node?. It should have a ?value? that it stores and also links to its parent and children (if they exist). Build getters and setters for it (e.g. parent node, child n
B Tree Unlike a binary-tree, every node of a B-tree may have a variable number of keys and children. The keys are stored in non-decreasing order. Every key has an associated ch
Double ended queues are implemented along doubly linked lists. A doubly link list can traverse in both of the directions as it contain two pointers namely left pointers and righ
One of the main problems with the linear queue is the lack of appropriate utilization of space. Assume that the queue can store 100 elements & the complete queue is full. Thus, it
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