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Depth-first traversal
A depth-first traversal of a tree visit a node and then recursively visits the subtrees of that node. Likewise, depth-first traversal of a graph visits a vertex and then recursively visits all the vertices adjacent to that node. The catch is that the graph may having cycles, but the traversal must visit each vertex at most once. The solution to the problem is to keep track of the nodes that have been visited, so that the traversal does not undergo the fate of infinite recursion.
Algo rithm to Insert a Node p at the End of a Linked List is explained below Step1: [check for space] If new1= NULL output "OVERFLOW" And exit Step2: [Allocate fr
Q. Give the algorithm for the selection sort. Describe the behaviours of selection sort when the input given is already sorted.
In the previous unit, we have discussed arrays. Arrays are data structures of fixed size. Insertion and deletion involves reshuffling of array elements. Thus, array manipulation
1. The following is a recursive algorithm to calculate the k -th power of 2. Input k a natural number Output kth power of 2 Algorithem: If k =0then return 1 Else return 2* po
Question 1 . Give the structure of PL/SQL Blocks and explain Question 2 . Differentiate between PL/SQL functions and procedures Question 3 . Explain the following Par
There are ten stations on a railway line: Train travels in both directions (i.e. from 1 to 10 and then from 10 to 1). Fare between each station is $2. A passenger input
I am looking for assignment help on the topic Data Structures. It would be great if anyone help me.
5. Implement a stack (write pseudo-code for STACK-EMPTY, PUSH, and POP) using a singly linked list L. The operations PUSH and POP should still take O(1) time.
Q. How do we represent a max-heap sequentially? Explain by taking a valid example. Ans: A max heap is also called as a descending heap, of size n is an almos
One of the main problems with the linear queue is the lack of appropriate utilization of space. Assume that the queue can store 100 elements & the complete queue is full. Thus, it
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