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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
when MT 2 and Gate is Negative In this case gate current flows through P 2 N 3 junction. Junction N 1 P 2 forward biased hence the triac starts conduction through P
WHAT IS DRIFT
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