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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
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Q. Explain Current-to-Current Amplifier ? The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y, i 1 + i S = i o S
#The requirement is as follows- There is a signal which is in the range of 0 to 5Hz. This signal frequency composition is to determined. The resolution of the determination is 1Hz.
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