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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
Q. An integrator as shown in Figure is to be designed to solve dy(t) / dt + 2000y (t) = 0 with y(0) = 5. If R i is chosen to be 10 k, find C f .
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