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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
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A ¼-hp, 230-V, 60-Hz, four-pole, single-phase inductionmotor has the following parameters and losses: R 1 = 10 , X l1 = X l2 = 12.5 ,R 2 = 11.5 , and X m = 250 . The core
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design 4 bit binary coded decimal to excess 3
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