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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
Q. A wye-connected, three-phase, 50-Hz, six-pole synchronous alternator develops a voltage of 1000 V rms between the lines when the rotor dc field current is 3A. If this alternator
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