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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
A 3 phase 400 volt(line to line) wye connected synchronous motor has Xs= 1 ohm per phase and a negligible armature resistance. The field current is so adjusted that the internal(in
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I want to know whether the circuits for both methods(linear polarization resistance and electrochemical impedance spectroscopy) are same or not?
angle of (1/1-ae^-jw)
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