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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
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A Class, "A" Amplifier is needed with the following specification: Collector Current = 5mA Needed offset voltage across RE= 2V Lowest input Frequency = 50Hz Use a BC108
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