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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
Q. In an amplifier, the maximum voltage gain is 1500 and occurs at 1kHz. It falls to 1060.5 at 20kHz and at 20Hz. Determine (i) lower cut-off frequency (ii) upper cut-o
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