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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
how to solve the circuit
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Using the BC548B BJT transistor amplifier biasing circuit of Lab 2 build an amplifier with the voltage gain of |A V | = 30 v/v ± = 10%. Measure all necessary parameters of the amp
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In this case, the armature is connected in series with the field coils. Thus I a = I f = I NB. At starting, the back emf is zero (because the m
Q. How many 500-page books can be stored on a 2400-ft, 1600-BPI magnetic tape if a typewritten page contains about 2500 bytes?
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