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Q. Explain Current-to-Current Amplifier ?
The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y,
i1 + iS = io
Since i1 = - vY /R1, Equation becomes
iS - vYR1 = io
Because X is a virtual ground, vY =-iSRf . Hence Equation becomes
The current gain is then given by
Components of GIS: 1. Software: GIS software gives the functions and tools required to store, analyze, and show geographical information. The key software elements are:
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Design a circuit using op-amp that will reject the 60kHz power line noise and also reject high signal frequency above 800Khz. The stop-band width around the 60kHz centre frequency
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Find the current through each resistor for the networking below using Mesh Analysis and Nodal Analysis.
Formulars.
Consider the circuit in Figure (a), which include a controlled source, and find the current in the 5-V source and the voltage across the 5- resistor by using (a) the loop-current
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Memory location 2000H has the word 5000H stored in it. What does each location contain after DEC WORD PTR [2000H].
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