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Q. Explain common collector configuration?
It is called the common-collector configuration because (ignoring the power supply battery) both the signal source and the load share the collector lead as a common connection point:
Since the emitter lead of a transistor is the one handling the most current (the sum of base and collector currents, since base and collector currents always mesh together to form the emitter current), it would be reasonable to presume that this amplifier will have a very large current gain .the current gain for a common-collector amplifier is quite large, larger than any other transistor amplifier configuration.
conditions where the transistor is conducting. Cutoff occurs at input voltages below 0.7 volts, and saturation at input voltages in excess of battery (supply) voltage plus 0.7 volts. Because of this behavior, the common-collector amplifier circuit is also known as the voltage-follower or emitter-follower amplifier. This amplifier configuration has a voltage gain of slightly less than 1In the common-collector configuration, though, the load is situated in series with the emitter, and thus its current is equal to the emitter current. With the emitter carrying collector current and base current, the load in this type of amplifier has all the current of the collector running through it plus the input current of the base. This yields a current gain of ? plus 1:
Q. Prove mathematically that the operating point does not depend on beta, in a potential divider bias circuit ? To determine the operating point, consider the input section of
hi I want the code of digital modulation in matlab with inputs binary bit stream and M-ar
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Write an assembly language program to determine average of 'n' integers. Ans MOV AX, 0000; Initial sum 0000 MOV BX, 0000 MOV SI, 0201H MOV CX, [SI] BACK: I
Q A high-pass filter circuit is shown in Figure. Using a PSpice program and PROBE, obtain the Bode magnitude plot for the transfer function ¯H(f) = ¯V out / ¯V in for frequency ra
function of a commutator in a DC motor
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RE should be made large enough to swamp out rB/ B. how does making RE large saturate the transistor b
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