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Q. Explain common collector configuration?
It is called the common-collector configuration because (ignoring the power supply battery) both the signal source and the load share the collector lead as a common connection point:
Since the emitter lead of a transistor is the one handling the most current (the sum of base and collector currents, since base and collector currents always mesh together to form the emitter current), it would be reasonable to presume that this amplifier will have a very large current gain .the current gain for a common-collector amplifier is quite large, larger than any other transistor amplifier configuration.
conditions where the transistor is conducting. Cutoff occurs at input voltages below 0.7 volts, and saturation at input voltages in excess of battery (supply) voltage plus 0.7 volts. Because of this behavior, the common-collector amplifier circuit is also known as the voltage-follower or emitter-follower amplifier. This amplifier configuration has a voltage gain of slightly less than 1In the common-collector configuration, though, the load is situated in series with the emitter, and thus its current is equal to the emitter current. With the emitter carrying collector current and base current, the load in this type of amplifier has all the current of the collector running through it plus the input current of the base. This yields a current gain of ? plus 1:
Three transformers are provided with the following rating values: 1) 2400/240 V, 55kVA, Req1 = (0.1 + 0.0Y) Ohm and Xeq1 = (0.15 + 0.XX) Ohm. 2) 240/120 V, 25kVA, Req1 = (0.1
p type material: p type material is formed by doping aerial crystal with impurity atoms having three valance electrons. The diffused impurities with three valence electrons
function of a commutator in a DC motor
HOW DOES A BRUSHLESS ALTERNATOR WORKS?
Q. Draw the complete circuit of a dual voltage source using 7805 and 7905. A voltage regulator is a circuit that supplies a constant voltage regardless of changes in load curre
Calculate the Maximum Power That Transmitted To the Load? A 25 MW load at the 33 kV receiving-end busbar of a short 3-phase transmission line has a power factor of 0.8 lagging.
A circular ring of magnetic material has a mean length of 1m and a cross sectional area of .001m^2.A sawcut of 5mm width is made in the ring . calculate the magnetizing current req
Vital parameters of regulator quality: 1. The output voltage's temperature coefficient of is the change in output voltage with temperature (perhaps averaged over a certain tem
Q. A BJT is biased by the method shown in Figure. If V BEQ = 0.7V, β = 100, V CEQ = 10 V, and I CQ = 5 mA, find I 1 , I 2 , and IEQ.
Q. Show the r-1s Complement? Subtract every digit of the number from r-1 (the radix of the system - 1)ex. 952 10
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