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Q. Explain common collector configuration?
It is called the common-collector configuration because (ignoring the power supply battery) both the signal source and the load share the collector lead as a common connection point:
Since the emitter lead of a transistor is the one handling the most current (the sum of base and collector currents, since base and collector currents always mesh together to form the emitter current), it would be reasonable to presume that this amplifier will have a very large current gain .the current gain for a common-collector amplifier is quite large, larger than any other transistor amplifier configuration.
conditions where the transistor is conducting. Cutoff occurs at input voltages below 0.7 volts, and saturation at input voltages in excess of battery (supply) voltage plus 0.7 volts. Because of this behavior, the common-collector amplifier circuit is also known as the voltage-follower or emitter-follower amplifier. This amplifier configuration has a voltage gain of slightly less than 1In the common-collector configuration, though, the load is situated in series with the emitter, and thus its current is equal to the emitter current. With the emitter carrying collector current and base current, the load in this type of amplifier has all the current of the collector running through it plus the input current of the base. This yields a current gain of ? plus 1:
Calculate the approximate donor binding energy Calculate the approximate donor binding energy for Si (r = 11.7,m x n = 1.18 m 0 ) Solution: From E= m * n q 4 / 2(4 πε 0
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SOD Output Serial output data single bit can be sent out through this pin using SIM command discussed in details in chapter8.
Compute the total capacitance with parallel connection: Three capacitors C 1 , C 2 and C 3 contain capacitance 20 μf, 15 μf, 30 μf, respectively. compute: 1. Charge on ea
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Hai.. i have been given a open loop transfer function to draw a bode plot with a particular K value and they asked me to find the value of K for which the phase margin becomes 45d
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Q. 10-kVA, 4800:240-V, 60-Hz, single-phase transformer has an equivalent series impedance of 120 + j300 referred to the primary high- voltage side. The exciting current of the tr
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