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Q. Explain biased and double clipper circuits.
Clipper can be either forward biased or reverse biased. If a battery is connected in series with the diode in a positive clipper,we get a biased clipper circuit.Here Vi is the input voltage given.VB is the voltage across the battery and output voltageis Vo.If the voltage level at input is greater than (Vi + VD) (VD is the voltage drop across the diode ,)which is .7V for silicon and .2V For germanium at 25 degree celcius,the diode conducts.The output voltage becomes (Vi + VD) at the instance input voltage exceeds (Vi + VD).If input voltage is less than this value dsiode is reverse biased and acts like an open switch.
In a biased negative clipper,both the polaritiesof the diode and battery are reversed. So a part of negative half cycle is cut off. Combination of positive and negative clipper is called a double clipper.Here a part of both negative and positive half cut off.
The clipping level for +ve clipper is (VB1 + VD1), where VD1 is the knee voltage of diode D1 and for diode 2 it is (VB2+ VD2) where VD2 is the knee voltage of diode D2.
Q. Determine the current I through the 10- resistor of the circuit of Figure by employing the node-voltage method. Check by mesh analysis.
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