Explain balanced wye-connected load, Electrical Engineering

Assignment Help:

Balanced Wye-Connected Load

Let us consider a three-phase, four-wire 208-V supply system connected to a balanced wye connected load with an impedance of 10 20° , as shown in Figure (a). We shall solve for the line currents and draw the corresponding phasor diagram.

Conventionally it is assumed that 208 V is the rms value of the line-to-line voltage of the supply system, and the phase sequence is positive, or A-B-C, unless mentioned otherwise. The magnitude of the line-to-neutral (or phase) voltages is given by 208/√3, or 120 V. Selecting the line currents returning through the neutral conductor, as shown in Figure, we have

1407_Balanced Wye-Connected Load.png

Note that ¯VBC has been chosen arbitrarily as the reference phasor, as in Figure (b). Assuming the direction of the neutral current toward the load as positive, we obtain

1532_Balanced Wye-Connected Load1.png

That is to say that the system neutral and the star point of the wye-connected load are at the same potential, even if they are not connected together electrically. It makes no difference whether they are interconnected or not.

Thus, for a balanced wye-connected load, the neutral current is always zero. The line currents and phase currents are equal inmagnitude, and the line currents are in phasewith the corresponding phase currents. The line-to-line voltages, in magnitude, are √3 times the phase voltages, and the phase voltages lag the corresponding line voltages by 30°.

The phasor diagram is drawn in Figure(b), from which it can be observed that the balanced line (or phase) currents lag the corresponding line-to-neutral voltages by the impedance

55_Balanced Wye-Connected Load2.png

angle (20° in our example). The load power factor is given by cos 20° for our problem, and it is said to be lagging in this case, as the impedance angle is positive and the phase current lags the corresponding phase voltage by that angle.

The problem can also be solved in a simpler way by making use of a single-line equivalent circuit, as shown in Figure(c),

303_Balanced Wye-Connected Load3.png

in which ¯ VL-N is chosen as the reference for convenience. The magnitude of the line current and the power factor angle are known; the negative sign associated with the angle indicates that the power factor is lagging. By knowing that the line (or phase) currents ¯IA, ¯IB, ¯IC lag their respective voltages ¯VAN, ¯VBN, and ¯VCN by 20°, the phase angles of various voltages and currents, if desired, can be obtained with respect to any chosen reference, such as ¯VBC.


Related Discussions:- Explain balanced wye-connected load

Find the new operating point in transistor, Q. A transistor in a fixed bias...

Q. A transistor in a fixed bias amplifier circuit was replaced by another transistor of beta equaling 150 instead of 60.if IB of transistor is equal to 100 microampere and collecto

Write explanatory notes on 8284 clock generator, Write explanatory notes on...

Write explanatory notes on 8284 Clock generator. The 8284 is an ancillary element to the microprocessors. Without this clock generator, a few additional circuits are needed to

Comparison of analog-modulation systems, Comparison of Analog-Modulation Sy...

Comparison of Analog-Modulation Systems The comparison of analog modulation systems (conventional AM, DSB SC, SSB SC, VSB, FM, and PM) can be based on three practical criteria:

Digital logic circuits, . In successive-approximation A/D converter, offset...

. In successive-approximation A/D converter, offset voltage equal to 1/2LSB is added to theD/A converter’s output. This is done to

Convolution, determine & sketch convolution y(n) of signal X(n)=an , -3 ...

determine & sketch convolution y(n) of signal X(n)=an , -3 0 , elsewhere H(n)=1 , 0 0 , elsewhere

Explain the 8259 microprocessor, Explain the 8259 microprocessor. 82...

Explain the 8259 microprocessor. 8259: The 8259A adds 8 vectored priority encoded interrupts to the microprocessor. This can be expanded to 64 interrupt requests with us

How can magnetic fields can be plot, The magnetic fields can be plot by usi...

The magnetic fields can be plot by using: i.  Compass ii.  Iron dust method  .

Differentiate between limiting and known errors, Q.   With suitable example...

Q.   With suitable examples differentiate between limiting and known errors. Sol. Limiting Errors (Guarantee Errors): The accuracy and precision of an instrument depends upon

Engineering drawing, connect two given points A and B by a parabolic curve ...

connect two given points A and B by a parabolic curve when OA=60mm,OB=80mm and angle AOB=110 degree

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd