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Explain Backtracking
The principal idea is to construct solutions single component at a time and evaluate such partially constructed candidates as follows.
If a partially constructed solution can be developed further without violating the problem's constraints, it is completed by taking the first remaining legitimate option for the next component.
If there is no legitimate option for the next component, no alternatives for any remaining component require to be considered.
Which data structure is required to change infix notation to postfix notation? Stack function is used to change infix notation to postfix notatio n
* Initialise d & pi* for each vertex v within V( g ) g.d[v] := infinity g.pi[v] := nil g.d[s] := 0; * Set S to empty * S := { 0 } Q := V(g) * While (V-S)
Algorithm for deletion of any element from the circular queue: Step-1: If queue is empty then say "queue is empty" & quit; else continue Step-2: Delete the "front" element
A town contains a total of 5000 houses. Every house owner has to pay tax based on value of the house. Houses over $200 000 pay 2% of their value in tax, houses over $100 000 pay 1.
Write an assembly program to separate the number of positive numbers and negative numbers from a given series of signed numbers.
Best Case: If the list is sorted already then A[i] T (n) = c1n + c2 (n -1) + c3(n -1) + c4 (n -1) = O (n), which indicates that the time complexity is linear. Worst Case:
Any binary search tree must contain following properties to be called as a red-black tree. 1. Each node of a tree should be either red or black. 2. The root node is always bl
Define Big Omega notation Big Omega notation (?) : The lower bound for the function 'f' is given by the big omega notation (?). Considering 'g' to be a function from the non-n
Define neotaxonomy. Discuss how electron microscopy can help in solving a zoological problem faced by taxonomist.
Q. Write down an algorithm to convert an infix expression into the postfix expression. Ans. Algo rithm to convert infix expression to post fix expression is given as
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