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Draw the hysteresis loop for a soft magnetic material and compare it with the hysteresis loop of hard magnetic material. Give two examples of each.
Soft and hard magnetic materials: All ferromagnetic materials are divided in two wide groups' soft and hard magnetic both materials.
Materials, that have, a steeply increasing magnetization curve, relatively small and narrow hysteresis loop and therefore small energy losses throughout cyclic magnetization are termed as soft magnetic materials. Therefore soft magnetic materials are utilized in building cores for use in alternating magnetic fields. Illustrations are nickel-iron alloy and soft ferrites. Figure below demonstrates a typical narrow hysteresis loop for soft magnetic materials.
Magnetic materials, that have a slowly rising magnetisation curve, large hysteresis loop area and huge energy losses for each cycle of magnetisation, are termed as hard magnetic materials. These materials are used for making permanent magnets. Illustrations are carbon steel, tungsten steel alnico. Figure below illustrates a broad hysteresis loop for hard magnetic materials.
Hysteresis curves for soft and hard magnetic
Q. A 75-kVA, 230/115-V, 60-Hz transformer was tested with these results: • Open-circuit test: 115 V, 16.3 A, 750 W • Short-circuit test: 9.5 V, 326 A, 1200 W Determine:
Demand Side Management Demand side management refers to programmes implemented through utilities to modify consumer load profile. Energy efficiency programmes decrease energy
Calculate the current flow in 30Ω resistor for the circuit in figure using Norton Theorem.
A TDM signal of the type is formed by samplingM voice signals at fs = 8 kHz. If the TDM signal then modulates the amplitude of a 4-MHz carrier for radio transmission, determine the
Q. Two single-phase transformers, each rated 2400: 120-V, are to be interconnected for (a) 4800:240- V operation, and (b) 2400:120-V operation. Draw circuit diagrams and show polar
Q. Explain Current-to-Current Amplifier ? The circuit given in Figure is to amplify a current fed to the input of the op amp. Applying KCL at Y, i 1 + i S = i o S
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current and voltage
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