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Q. Explain about Register marker?
Register marker: Stronger selectors perform searching and counting . Though, the crossbar switch has no ‘intelligence'. Something external to switch should decide which magnets to operate. This is known as a Register Marker. As it takes less than a second to operate the switch, a marker can control many switches as well as serve many registers. So even a large exchange needs few markers. This is further stage of common control, which we willcall centralized control.
P-N Junction A p-n junction is made by joining P-type and N-type semiconductors together in extremely close contact. The word junction consider to the boundary interface
Determine the value of Resistance: Determine the value of R, so that the condition for resonance is fulfilled Figure Solution Admittance of first branch
Q. Show Steady-State Sinusoidal Analysis with PSpice PSpice can easily solve steady-state ac circuits for currents and voltages. Ac voltage sources, which must begin with the l
Q. Principle of Three-phase synchronous machines? In fact, with very few exceptions, three-phase synchronous machines are most commonly used for power generation. In general, t
Name the special functions registers available in 8051. Accumulator B Register Program Status Word. Stack Pointer. Data Pointer. Port 0 Port 1 Port 2 Po
Antenna Fundamentals We shall discuss here only the fundamental concepts needed to understand the role of an antenna as a power-coupling element of a system. Figure illustrates
What is extended data output RAM? EDO RAM: A slight modification to the DRAM structure changes the device in an EDO (extended data output) DRAM device. Inside the EDO memory, a
Q. Input offset voltage of operational amplifier? When both inputs are tied to ground, i.e., both differential-mode and common-mode inputs are zero, the output should be zero.
Current ratio The ratio is mainly used to give an idea of the company's ability to pay back its short-term liabilities with its short-term assets. The higher the current ratio
when MT 2 and Gate is Negative In this case gate current flows through P 2 N 3 junction. Junction N 1 P 2 forward biased hence the triac starts conduction through P
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