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Q. Explain about Differentiator?
Shown in Figure is a differentiator which is obtained by replacing R1 in the inverting amplifier of Figure by a capacitor C. Assuming ideal op-amp characteristics, one has i = iC and vo = - Ri = - RiC. But since iC (t) = Cdvin (t) /dt ,we get
vo (t) = - RC dvin (t) / dt
which corresponds to a differentiator with a gain of -RC. In practice, however, differentiators are normally avoided because of high-frequency noise (which is accentuated due to a transfer function that increases with frequency) and stability problems (which make them oscillate).
Q. Prove mathematically that the operating point does not depend on beta, in a potential divider bias circuit ? To determine the operating point, consider the input section of
Three sine waves along with frequencies 100Hz, 200Hz and 350Hz and with amplitudes of 1V, 2V and 1.5V correspondingly, are added together to make a single waveform. What is the min
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Q. Consider themagnetic circuit of Figure. Let the cross-sectional area AC of the core, be 16 cm 2 , the average length of the magnetic path in the core lC be 40 cm, the number
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Q. A 230-V, single-phase, 60-Hz source supplies two loads in parallel. One draws 10 kVA at a lagging power factor of 0.80 and the other draws 6 kWat a lagging power factor of 0.90.
I`m a 3rd year electrical engineering student studying in Canada, and there is a new course they added in my university for 3rd year students called Engineering Project. from the
Q. Show output Characteristic Of Common Emitter Configuration? Output characteristics: This family of curves may be divided into three regions just as was done for common base
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