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Q. Explain about Deadlocks?
Deadlocks
for (int i = 0; i < n; i++) {
// first find a thread that can finish
for (int j = 0; j < n; j++) {
if (!finish[j]) {
boolean temp = true;
for (int k = 0; k < m; k++) {
if (need[j][k] > work[k])
temp = false;
}
if (temp) { // if this thread can finish
finish[j] = true;
for (int x = 0; x < m; x++)
work[x] += work[j][x];
At present there are two resources available. It is an system is in an unsafe state as process P1 could complete thereby freeing a total of four resources. But we can't guarantee that processes P0 and P2 can complete. Nevertheless it is possible that a process may release resources before requesting any further. For instance process P2 could release a resource thereby increasing the total number of resources to five. This permit process P0 to complete which would free a total of nine resources thereby allowing process P2 to complete as well.
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Explain Wait for Graph a. Use a resource allocation graph to derive a wait-for graph. b. Wait-for graph acquired by making an edge from p 1 to p 2 iff p 1 is waiting for
The optimal replacement policy, called OPT, is to evict the page which will be accessed farthest into the future. Since we can't predict the future precisely, we can't implement OP
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Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4
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Define lazy swapper. Rather than swapping the entire process into main memory, a lazy swapper is used. A lazy swapper never swaps a page into memory unless that page will be ne
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