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Q. Explain about Deadlocks?
Deadlocks
for (int i = 0; i < n; i++) {
// first find a thread that can finish
for (int j = 0; j < n; j++) {
if (!finish[j]) {
boolean temp = true;
for (int k = 0; k < m; k++) {
if (need[j][k] > work[k])
temp = false;
}
if (temp) { // if this thread can finish
finish[j] = true;
for (int x = 0; x < m; x++)
work[x] += work[j][x];
At present there are two resources available. It is an system is in an unsafe state as process P1 could complete thereby freeing a total of four resources. But we can't guarantee that processes P0 and P2 can complete. Nevertheless it is possible that a process may release resources before requesting any further. For instance process P2 could release a resource thereby increasing the total number of resources to five. This permit process P0 to complete which would free a total of nine resources thereby allowing process P2 to complete as well.
mention the three problems that mat be caused by wrong initialization and placement of wait() and signal()operations in the use of semaphore
Now let's implement bounded producer-consumer with semaphores, a Coke machine which is initially empty: semaphore sem_mutex = 1 // binary semaphore for mutual exclusion, 1==unlo
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Can you give me assistance on my operating system assignment?
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