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Q. Explain about Centrifugal force?
The centrifugal force is
Fc =mv2/r,
Where r is the radius of the orbit and m is the mass of the object and v is the velocity. The orbital radius is assumed approximately equal to the earth's
Radius for low orbit, The gravitational force is
Fg = -mg,
Where g is the acceleration due to gravity, We are again assuming low orbit.
Then Fc + Fg = 0 and
mv2/r= mg
v2= gr, and,
v =√gr.
Assuming earth's radius to be 3960 miles and the acceleration due to gravity is 32 feet per second2 , we have
v = √32/5280 × 3960
v = 4.9mi/sec.
what is the force?
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Q. A small telescope has an objective lens of focal length 144cm and an eyepiece of focal length 6.0cm.What is the magnifying power of the telescope? What is the separation between
DERIVATION OF ANGLE OF DEVITAION
is there any Law of Physics acting in a weighted object placed in a corrugated paper and the paper can actually support it well thanky you :)
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initial position time the vibration mean time time period of the bob t time
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