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Example of Word problem:
There is a man who is 21 years older than his son. 5 years ago he was four times as old as his son. How older are both now?
Solution:
Step 1. Let x = Son's Age Now
Step 2. Then,
x + 21 = Father's Age Now
x - 5 = Son's Age Five Years Ago
(x + 21) - 5 = Father's Age Five Years Ago
Step 3. 5 years ago the father was four times as old as his son. (x + 21) - 5 = 4(x - 5)
Step 4. (x + 21) - 5 = 4(x - 5)
x + 16 = 4x - 20
x - 4x = -20 - 16
-3x = -36
x = 12 years
Solving for the other unknowns:
x + 21 = 12 + 21
x + 21 = 33 years
Answers: Son's Age Now = 12 years
Father's Age Now = 33 years
Step 5. The man is 21 years older than his son.
12 + 21 = 33 years
Five years ago he was four times as old as his son.
33 - 5 = 28 = 4(12 - 5) = 4 x 7
Thus, the answers check.
A comparison of the wearing out quality of two types of tyres was obtained by road testing. Samples of 100 tyres were collected. The miles traveled until wear out were recorded and
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