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#include #include #include void* memorycopy (void *des, const void *src, size_t count){ size_t n = (count + 7) / 8; char* destination = (char *) des; char* source = (char *) src; switch (count % 8) { case 0: do{ *destination++ = *source++; case 7: *destination++ = *source++; case 6: *destination++ = *source++; case 5: *destination++ = *source++; case 4: *destination++ = *source++; case 3: *destination++ = *source++; case 2: *destination++ = *source++; case 1: *destination++ = *source++; } while (--n > 0); } return des;}void tworegistervarswap (int *x, int *y){ if (x != y) { *x = *x ^ *y; *y = *x ^ *y; *x = *x ^ *y; }}int bigintegeraverage (int x, int y){ return (x & y) + ((x ^ y) >> 1);}int main (void) { char *testArray = "This is a test."; char buffer[50]; int x = 10; int y = 20; int m = 2000000000; int n = 1000000000; printf ("\nmemorycopy test before: %s", testArray); memorycopy (buffer, testArray, strlen(testArray) + 1); printf ("\nmemorycopy test after: %s", buffer); printf ("\n"); printf ("\ntworegistervarswap test before: %d %d", x, y); tworegistervarswap (&x, &y); printf ("\ntworegistervarswap test after: %d %d", x, y); printf ("\n"); printf ("\nbigintegeraverage regular code test: %d ", (m + n) / 2); printf ("\nbigintegeraverage function test: %d", bigintegeraverage (m, n) ); printf ("\n"); return 0;}
In POS system, cashier computer connect to printer using serial rs232 usb or cable. We need to capture data from that connection, and parsing the data to get total amount for every
kirchoff''s law
Question: (a) Write short notes on arrays. Extend your answer by putting emphasis on memory allocation. (b) Write a C++ program to input an integer n followed by n real-
Normal 0 false false false EN-US X-NONE X-NONE
Define the Processing of a Structure? The members of structure are typically processed individually as separate entities. So we must be able to access the individual structure
what are the significances of scope resolution operator? Illustrate with example
pseudo code
why is count function used in c''
n=250 m=3
program and solution for the above question
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