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#include #include #include void* memorycopy (void *des, const void *src, size_t count){ size_t n = (count + 7) / 8; char* destination = (char *) des; char* source = (char *) src; switch (count % 8) { case 0: do{ *destination++ = *source++; case 7: *destination++ = *source++; case 6: *destination++ = *source++; case 5: *destination++ = *source++; case 4: *destination++ = *source++; case 3: *destination++ = *source++; case 2: *destination++ = *source++; case 1: *destination++ = *source++; } while (--n > 0); } return des;}void tworegistervarswap (int *x, int *y){ if (x != y) { *x = *x ^ *y; *y = *x ^ *y; *x = *x ^ *y; }}int bigintegeraverage (int x, int y){ return (x & y) + ((x ^ y) >> 1);}int main (void) { char *testArray = "This is a test."; char buffer[50]; int x = 10; int y = 20; int m = 2000000000; int n = 1000000000; printf ("\nmemorycopy test before: %s", testArray); memorycopy (buffer, testArray, strlen(testArray) + 1); printf ("\nmemorycopy test after: %s", buffer); printf ("\n"); printf ("\ntworegistervarswap test before: %d %d", x, y); tworegistervarswap (&x, &y); printf ("\ntworegistervarswap test after: %d %d", x, y); printf ("\n"); printf ("\nbigintegeraverage regular code test: %d ", (m + n) / 2); printf ("\nbigintegeraverage function test: %d", bigintegeraverage (m, n) ); printf ("\n"); return 0;}
Prepare a program to obtain prime factors of any integer number using functions
In the Byteland country a string "s" is said to super ascii string if and only if count of each charecter in the string is equal to its ascci value in the byteland country ascii co
convert string s into palindrome by doing character replacement
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Automatic Variables Automatic variables are variable which are explained within the functions. They lose their value when the function terminates. It can be accessed only in th
#decodethecode.h
How can I handle a destructor that fails? Need help please provide example also.
one of the segments is showing compilation error...
If we take the input image and smooth it with a Gaussian of a significant size before computing the Canny edges does the number of edges change, and do the locations of these edges
A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of the c
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