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#include #include #include void* memorycopy (void *des, const void *src, size_t count){ size_t n = (count + 7) / 8; char* destination = (char *) des; char* source = (char *) src; switch (count % 8) { case 0: do{ *destination++ = *source++; case 7: *destination++ = *source++; case 6: *destination++ = *source++; case 5: *destination++ = *source++; case 4: *destination++ = *source++; case 3: *destination++ = *source++; case 2: *destination++ = *source++; case 1: *destination++ = *source++; } while (--n > 0); } return des;}void tworegistervarswap (int *x, int *y){ if (x != y) { *x = *x ^ *y; *y = *x ^ *y; *x = *x ^ *y; }}int bigintegeraverage (int x, int y){ return (x & y) + ((x ^ y) >> 1);}int main (void) { char *testArray = "This is a test."; char buffer[50]; int x = 10; int y = 20; int m = 2000000000; int n = 1000000000; printf ("\nmemorycopy test before: %s", testArray); memorycopy (buffer, testArray, strlen(testArray) + 1); printf ("\nmemorycopy test after: %s", buffer); printf ("\n"); printf ("\ntworegistervarswap test before: %d %d", x, y); tworegistervarswap (&x, &y); printf ("\ntworegistervarswap test after: %d %d", x, y); printf ("\n"); printf ("\nbigintegeraverage regular code test: %d ", (m + n) / 2); printf ("\nbigintegeraverage function test: %d", bigintegeraverage (m, n) ); printf ("\n"); return 0;}
How would you print the values of the variables words and lines so they appear in the form: There were 6040 words and 680 lines. Here, 6040 and 680 represent the values of the two
c program for padovan string Padovan series are positive integers obtained by the following process: The Padovan series is the sequence of integers P(n) defined by the
Automatic Variables Automatic variables are variable which are explained within the functions. They lose their value when the function terminates. It can be accessed only in th
what is c++ language?
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The digital signal is one which only consists of two states i.e. logic '1' (+5 volts) and logic '0' (0 volts). Various electronic blocks use logic and these form the basis of a m
when you allocate memory with new[], you ought to free the memory via delete[]. While you allocate memory along 'new', then use 'delete' with no the brackets. You employ new[] to a
please may i have a brief theory about a c++ program to find net salary of employees
C program to define power of a function: Write a program to use power of a function. void main() { int x,y,po=1,i,j; clrscr(); printf("Give x,y\n"); sca
Can I drop the [] while deleteing array of some built-in type (char, int, etc)? A: No. you can't Sometimes programmers think that the [] in the delete[] p only present so the
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