Example of simple exponential smoothing, Mechanical Engineering

Assignment Help:

Example of simple exponential smoothing:

A TV manufacturer utilizes simple exponential smoothing with α = 0.1 to forecast demand. For the first week of March, the forecast was 400 units while actual demand turned out to be 370 units.

1. Forecast the demand for the second week of March.

2. If the actual demand for the second week turned out to be 417 units, forecast the demand for the 3rd week. Continue forecasting for the subsequent four weeks. You can take actual demands for the subsequent weeks as 409, 388, 377, 445, and 410 units.

3. Develop an adjusted exponential forecast for this company. You may assume the initial trend adjustment factor Tt as zero and β = 0.1.

Solution

(a) Ft + 1 = Ft + α (Dt - Ft)

                     = 400 + 0.1 (370 - 400) = 397 units.

 (b)

707_Adjusted Exponential Smoothing.png

(c)        The trend adjustment is accomplished by total of a correction factor

[(( 1 -β )/ β ) Tt +1 )]   to the simple exponential forecast.

As the initial trend adjustment factor (given) Tt = 0, we have

March 1st Week

Tt + 1 = β (Ft + 1 - Ft) + (1 - β) Tt

= 0.1 (397 - 400) + (0.9) (0) = - 0.30

T(t +1) adj = Ft +1 +( 1 -β / β )T t +1

= 397 +( 0.9/0.1)  (- 0.30) = 394.30

The adjusted forecast for the second week of March = 394.30.

March 2nd Week

Tt + 1 = 0.1 (399 - 397) + (0.9) (- 0.30)

= 0.2 - 0.27 = - 0.07

F(t + 1) adj = 399 + 9 (- 0.07) = 398.37

The remaining values may be put in table form, as below.

606_Adjusted Exponential Smoothing1.png

The trend-adjusted forecast for the third week of April is Ft, adj   = 393.54 units whereas simple exponential forecast for the same week is 400 units.

The main reason for broad use of simple and adjusted exponential smoothing is that the forecast may be computerized quickly, requires very little memory space, and data can be updated easily. These methods are specifically useful to firms which have thousands of items in inventory. Since each forecast value contains all past forecast and demand data in the properly exponentially weighted manner, there is no requirement to maintain records of historical data (as in case of arithmetic moving averages). It is an effective and efficient method of forecasting with a built-in means of tracking the average while discounting the erratic random fluctuations.


Related Discussions:- Example of simple exponential smoothing

Find out the centroid of the shaded area, Find out the centroid of the shad...

Find out the centroid of the shaded : Find out the centroid of the shaded area shown in Figure Solution Net area of shaded portion of Figure = The area of full

Safety benefits - industrial safety, Safety Benefits - Industrial Safety ...

Safety Benefits - Industrial Safety An industry or a company which follows safety programmes is benefitted in several ways. The benefits are shared among employer and employee

Determine the initial radius of curvature, Determine the initial radius of ...

Determine the initial radius of curvature:  A carriage spring, defiantly loaded and simply supported at its ends, has 12 steel plates each 60 mm wide by 6 mm thick. If the lon

Explain single piece pattern, Single piece pattern These are inexpensiv...

Single piece pattern These are inexpensive and the simplest type of patterns. As the name indicates, they are made of a single piece as shown in Figure.2.2 this type of pattern

Describe the slope - area method, Q. Describe the Slope - Area Method? ...

Q. Describe the Slope - Area Method? In the event of infeasibility of Velocity Area method on account of either rapid rise or fall of floods or lack of equipment or any other r

Working principle of the petrol engine, W orking Principle of the Petrol E...

W orking Principle of the Petrol Engine: OTTO CYCLE     5-1 Suction Stroke 1-2 Adiabatic Compression Stroke 2-3 Heat Addition at the constant Volume.

Group technology, what are the limitations of group technology and life cyl...

what are the limitations of group technology and life cyle issues in group technology

Newtons third law, Problem - Newton's Third Law Newton's Third Law of M...

Problem - Newton's Third Law Newton's Third Law of Motion states that if two objects interact, the force F 12 exerted by object 1 on object 2 is equal in magnitude and oppos

Determine the types of evolutionary cad applications, Determine the Types o...

Determine the Types of Evolutionary CAD applications Evolutionary CAD applications supporting design can be categorized into three types - traditional, knowledge based, and im

Dislocation, Diff. B/w edge and screw dislocation

Diff. B/w edge and screw dislocation

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd