Example of mixing problems, Algebra

Assignment Help:

How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?

Solution

Let x is the amount of 50% solution which we need.  It means that there will be gallons of the 40% solution once we're done mixing the two.

Following is the basic work equation for this problem.

1357_Mixing Problems1.png

Now, plug in the volumes & solve for x.

0.5x + 0.35 (10) =0.4 ( x + 10)

0.5x + 3.5 + 0.4x + 4

0.1x + 0.5

x =0.5/0.1 = 5 gallons

Thus, we required 5 gallons of the 50% solution to get a 40% solution.


Related Discussions:- Example of mixing problems

Completing the square process, As a last topic in this section we have to b...

As a last topic in this section we have to briefly talk about how to take a parabola in the general form & convert it into the following form

Solving quadratic functions, Sum of two numbers is 10 and their multipicati...

Sum of two numbers is 10 and their multipication is 21,find the two numbers. x^2 -10x +21=0

Hcf, how to find hcf easily

how to find hcf easily

Center of the ellipse, Note that the right side has to be a 1 to be in stan...

Note that the right side has to be a 1 to be in standard form.  The point ( h, k ) is called the center of the ellipse. To graph the ellipse all that we required are the left mo

Mixing problems, It is the final type of problems which we'll be looking at...

It is the final type of problems which we'll be looking at in this section.  We are going to be looking at mixing solutions of distinct percentages to obtain a new percentage. The

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd