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How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
Solution
Let x is the amount of 50% solution which we need. It means that there will be gallons of the 40% solution once we're done mixing the two.
Following is the basic work equation for this problem.
Now, plug in the volumes & solve for x.
0.5x + 0.35 (10) =0.4 ( x + 10)
0.5x + 3.5 + 0.4x + 4
0.1x + 0.5
x =0.5/0.1 = 5 gallons
Thus, we required 5 gallons of the 50% solution to get a 40% solution.
simplify the following expressions for the given values x3 -x2/x2 -x x=3 how do i do this to get answer need step by step instruction
1/3x-2/3= 1/2(1-3x)
if A is an ideal and phi is onto S,then phi(A)is an ideal.
x2 -x = 7 -3 -5 1 5 -3
14th term 60,68,76,84,92
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