Example of mixing problems, Algebra

Assignment Help:

How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?

Solution

Let x is the amount of 50% solution which we need.  It means that there will be gallons of the 40% solution once we're done mixing the two.

Following is the basic work equation for this problem.

1357_Mixing Problems1.png

Now, plug in the volumes & solve for x.

0.5x + 0.35 (10) =0.4 ( x + 10)

0.5x + 3.5 + 0.4x + 4

0.1x + 0.5

x =0.5/0.1 = 5 gallons

Thus, we required 5 gallons of the 50% solution to get a 40% solution.


Related Discussions:- Example of mixing problems

Add, add - 3a + b - 10 -6c, c -d- a + 9 and - 4c +2a - 3b - 7

add - 3a + b - 10 -6c, c -d- a + 9 and - 4c +2a - 3b - 7

Varibles, 2x-1=10 I got 9/2 but i''m not sure if that is really right

2x-1=10 I got 9/2 but i''m not sure if that is really right

Logarithm functions, Logarithm Functions In this section now we have t...

Logarithm Functions In this section now we have to move into logarithm functions. It can be a tricky function to graph right away.  There is some different notation which you

Write & Solve Equations, Lisa and Judy read mystery novels. Judy has read ...

Lisa and Judy read mystery novels. Judy has read three fewer than five times as many as Lisa. Equation: J=5L-3 Lisa: Judy:

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd