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How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
Solution
Let x is the amount of 50% solution which we need. It means that there will be gallons of the 40% solution once we're done mixing the two.
Following is the basic work equation for this problem.
Now, plug in the volumes & solve for x.
0.5x + 0.35 (10) =0.4 ( x + 10)
0.5x + 3.5 + 0.4x + 4
0.1x + 0.5
x =0.5/0.1 = 5 gallons
Thus, we required 5 gallons of the 50% solution to get a 40% solution.
(2,9);y=3x-1
I want to know the solution of this problem: log2.log3(x+2)=2
39+(-88)-29-(-83)
BEST WAY TO FIND ORDERED PAIRS
Sketch the graph parabolas. g ( x ) = 3x 2 - 6 x + 5 Solution For this parabola we've obtain a = 3 , b = -6 and c = 5 . Ensure that you're cautious with signs while id
need help with homework
I have 4.80 I need to separste into nichols, dimes and pennies. The first digit has to equal The first digist is l1 less the the first and the 2nd is once less than the third and
(9x-3)(x+6)
17b-29=39
If m
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