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How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?
Solution
Let x is the amount of 50% solution which we need. It means that there will be gallons of the 40% solution once we're done mixing the two.
Following is the basic work equation for this problem.
Now, plug in the volumes & solve for x.
0.5x + 0.35 (10) =0.4 ( x + 10)
0.5x + 3.5 + 0.4x + 4
0.1x + 0.5
x =0.5/0.1 = 5 gallons
Thus, we required 5 gallons of the 50% solution to get a 40% solution.
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need help with homework
Solve following. 2 x - 4 = 10 Solution There actually isn't much to do other than plug into the formula. As with equations p merely represents whatever is within the a
(-3) EVALUATE X3 -2X2 + 6X -64
HOW TO FACTOR THE GIVEN
a^2-b^2-c^2-2bc
Do you have any helpful hints for solving equations?
Qs1=-7+P1 (2) Qd1=15-P1+2P2+P3 (3) Qs1=Qd1
2x+3
a+1/2=1
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