Example of mixing problems, Algebra

Assignment Help:

How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution?

Solution

Let x is the amount of 50% solution which we need.  It means that there will be gallons of the 40% solution once we're done mixing the two.

Following is the basic work equation for this problem.

1357_Mixing Problems1.png

Now, plug in the volumes & solve for x.

0.5x + 0.35 (10) =0.4 ( x + 10)

0.5x + 3.5 + 0.4x + 4

0.1x + 0.5

x =0.5/0.1 = 5 gallons

Thus, we required 5 gallons of the 50% solution to get a 40% solution.


Related Discussions:- Example of mixing problems

Geometry, how do you do proofs?

how do you do proofs?

Constant function, It is probably the easiest function which we'll ever gra...

It is probably the easiest function which we'll ever graph and still it is one of the functions which tend to cause problems for students. The most general form for the constant

Verticies, how many does a rhombus have

how many does a rhombus have

Unitary method, What are the pre conditions to applying unitary method to a...

What are the pre conditions to applying unitary method to a given problem? e.g. We know that 37 degrees celsius is equal to 98.6 degrees fahrenheit, but 1 degrees celsius is not eq

FACTORING, HOW TO FACTOR THE GIVEN

HOW TO FACTOR THE GIVEN

Steve, The following equalities can be used to make conversion factors. 2....

The following equalities can be used to make conversion factors. 2.54 cm = 1 inch 12 inches = 1 foot 1 mile = 5,280 feet 100 cm = 1 m 1000 m = 1 km 36 inches = 1 y

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd