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Here are two one-to-one functions f (x ) and g ( x ) if
(f o g )( x ) = x AND ( g o f ) ( x ) = x
then we say that f ( x )& g ( x ) are inverses of each other. More particularly we will say that g ( x ) is the inverse of f ( x ) and specified it by
g ( x ) = f -1 ( x )
Similarly we could also say that f ( x ) is the inverse of g ( x )and specified it by
f (x ) = g -1 ( x )
The notation which we use really based upon the problem. In most of the cases either is acceptable.
For the two functions which we started off this section along with we could write either of the following two sets of notation.
f ( x ) = 3x - 2 f -1(x) = x /3+ 2/3
g ( x ) = x/3 + 2/3 g -1 (x ) = 3x - 2
Now, be careful along with the notation for inverses. The "-1" is not an exponent in spite of the fact that is certain does look like one! While dealing with inverse functions we've got to keep in mind that
f-1(x) ≠ 1/ f ( x )
In the earlier two sections we've talked quite a bit regarding solving quadratic equations. A logical question to ask at this point is which method has to we employ to solve a giv
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Vertical asymptote In our graph as the value of x approaches x = 0 the graph begin gets extremely large on both sides of the line given by x = 0. This line is called a vertical
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a farmer has a garden with 2 sides at right angles and the third side is 423ft.long.find the perimeter of the garden. if the angle between the shortest and the longest side is 58''
write the expression in exponential form 6^sqrt9^3
I don''t understand anything!
log(mn)
Example : Sketch the graph of hyperbolas. ( x - 3) 2 /25 - ( y + 1) 2 /49 =1 Solution Now, notice that the y term contain the minus sig
As noted earlier most parabolas are not given in that form. So, we have to take a look at how to graph a parabola which is in the general form.
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