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Example
Reduce 24/36 to its lowest terms. 24/36=12/18=6/9=2/3. In the first step we divide the numerator and the denominator by 2. The fraction gets reduced to 12/18. We divide this fraction again by 2. It stands reduced to 6/9. This we divide by 3. We obtain 2/3. Thus, we say that the fraction 24/36 has been reduced to its lowest terms, which happens to be a fraction 2/3.
The two sides of a triangle are 17 cm and 28 cm long, and the length of the median drawn to the third side is equal to 19.5 cm. Find the distance from an endpoint of this median to
simplify the following: 3^5/2-3^1/2
In the introduction of this section we briefly talked how a system of differential equations can occur from a population problem wherein we remain track of the population of both t
Area with Polar Coordinates In this part we are going to look at areas enclosed via polar curves. Note also that we said "enclosed by" in place of "under" as we usually have
ABC is a right angled triangle in which ∠A = 900. Find the area of the shaded region if AB = 6 cm, BC=10cm & I is the centre of the Incircle of ?ABC. Ans: ∠A =90 0 BC
These experiences should be related to the mathematical concepts and ideas that we teach them. Only then will these ideas appear relevant to the children, and be absorbed by them
greens function for x''''=0, x(1)=0, x''(0)+x''(1)=0 is G(t,s)= {1-s for t or equal to s
Applications of derivatives : At last, let's not forget about our applications of derivatives. Example Assume that the amount of air in a balloon at any time t is specified
#What is an easy way to find the area of any figure
how to use matlab to reverse digits of integer using mod
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