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Factor by grouping each of the following.
3x2 - 2x + 12x - 8
Solution
In this case we collect the first two terms & the final two terms as illustrated here,
(3x2 - 2x ) + (12 x - 8)
Notice that we can factor an x out of the first grouping & a 4 out of the second grouping. Doing this gives,
3x2 - 2x + 12x - 8=x (3x - 2) + 4 (3x - 2)
Now we can see that we can factor out a common factor of 3x - 2 thus let's do that to the final factored form.
3x2 - 2x + 12x - 8 = (3x - 2) ( x + 4)
And we're done. That's all that there is to factoring through grouping. Note down again that it will not always work & sometimes the single way to know if it will work or not is to attempt it and see what you get.
jeff left hartford at 2:15 pm and arrived in boston at 4:45 pm how long did the drive take him?
2+4
what Is the common denominator for 1/2 and 1/4
1 1/3:2/3:1/6
Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
Please, I want to know and study "stability 0n predictor -corrector method .My gmail is [email protected] heap and kind to me .Thanks for this.
how to introduce the topic?
1+2x
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