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Example:
Consider the following relations:
ROLLNO
NAME
ADDRESS
COURSE_ID
100
Kanupriya
234, Saraswati Vihar.
CS1
101
Rajni Bala
120, Vasant Kunj
CS2
102
Arpita Gupta
75, SRM Apartments.
CS4
STUDENT
Course
COURSE ID
COURSE_NAME
DURATION
BCA
3yrs
MCA
CS3
M.Sc.
2yrs
B.Sc.
CS5
MBA
If we want to show name of all the students with their course details then natural join is used in the following method:
STUDENT COURSE
Resultant relation will be as follows:
If R2 R3= R1 ÷ R2 If R2 R3= R1 ÷ R2
Student
234, Saraswati
Vihar.
Arpita
Gupta
75, SRM
Apartments.
There are some other types of joins like outer joins.
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Introductory course and so does not require any fancy coding. I will provide a guidance document to help you in producing the solutions.
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