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Solve following.
|2x - 5 |= 9
Solution
Now, recall that absolute value does not just make all minus signs in plus signs. In order to solve these we've got to employ the formula above as in all cases the number on the right side of the equal sign is positive.
There actually isn't much to do here other than using the formula from above as noted above. All we have to note is that in the formula above p represents whatever is on the inside of the absolute value bars and so in this case we have,
2 x - 5 = -9 or 2 x - 5 = 9
At this instance we've got two linear equations which are easy to solve.
2 x = -4 or 2 x = 14
x = -2 or x = 7
Thus, we've got two solutions to the equation
x = -2 and x =7 .
Now, let's take a look at how to deal with equations for which b is zero or negative. We'll do this with an example.
The last set of transformations which we're going to be looking at in this section isn't shifts, but in spite of they are called reflections & there are two of them. Reflection
find the perimeter of an irregulary shapep blocks of land didvided into 4 Triangles ab=12m by 15m bc =15m by 60m cd =24m by25m da = 25m by 48m..
-3x+4y>-12
Solve following equations. y -6 - 9 y -3 + 8 = 0 Solution y -6 - 9 y -3 + 8 = 0 For this part notice that, -6 = 2 (
how do you do equations for sloe intercept?
3X^8+6X^7-9X^6+6X^5 FACTOR THE EXPRESSION
if A is an ideal and phi is onto S,then phi(A)is an ideal.
5/4:3/7
f(x)=5x2=5x-2 f(3)
Example Solve 3x 2 - 2 x -11 = 0. Solution In this case the polynomial doesn't factor thus we can't do that step. Though, still we do have to know where the polynomial i
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