Example of absolute value equations, Algebra

Assignment Help:

Solve following.

                                 |2x - 5 |= 9

Solution

Now, recall that absolute value does not just make all minus signs in plus signs. In order to solve these we've got to employ the formula above as in all cases the number on the right side of the equal sign is positive.

There actually isn't much to do here other than using the formula from above as noted above.  All we have to note is that in the formula above p represents whatever is on the inside of the absolute value bars and so in this case we have,

                                                           2 x - 5 = -9          or    2 x - 5 = 9

At this instance we've got two linear equations which are easy to solve.

2 x = -4           or         2 x = 14

x = -2  or       x = 7

Thus, we've got two solutions to the equation

                      x = -2 and    x =7 .

 

Now, let's take a look at how to deal with equations for which b is zero or negative.  We'll do this with an example.


Related Discussions:- Example of absolute value equations

Problem Solving, In a yacht race the second leg was half the length of the ...

In a yacht race the second leg was half the length of the first leg, the third leg was two-thirds of the second leg, and the last leg was twice the length of the second leg. If the

Algebra 2, Find the zeros of the function by using the quadratic formula. ...

Find the zeros of the function by using the quadratic formula. Simplify your answer as much as possible. g(x)= 2x^2+4x-12

Method of elimination, Now let's move into the next technique for solving s...

Now let's move into the next technique for solving systems of equations.  As we illustrated in the example the method of substitution will frequently force us to deal with fraction

Inequalities, Labrador retrievers that compete in field trials typically co...

Labrador retrievers that compete in field trials typically cost $2,000 at birth. Professional trainers charge $400 to $1,000 per month to train the dogs. If the dog is a champion b

Student, find the level of illumination for four fixtures rated at 2800 lum...

find the level of illumination for four fixtures rated at 2800 lumens each if the coefficient of depreciation is 0.75, the coefficient of utilization is 0.6, and the area of the ro

Graphing, #question.P(x) = –x2 + 110x – 1,000. P(5), P(50), P(120) plot on ...

#question.P(x) = –x2 + 110x – 1,000. P(5), P(50), P(120) plot on graph

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd