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Q. An 8 - pole dc generator has 500 armature conductors and has a useful flux per pole of 0.065 web. What will be the emf generated if it is lap connected and runs at 1000 r.p.m. What must be the speed at which it is to be driven to produce the same emf if it is wave wound?
Ans.
E1 = N1PΦZ/60A = 10000 × 0.065 ×500 × P/A
For lap connection A = P
E1 = 10000 × 0.065 ×500 /60 = 541.67 volts
E2 = N28ΦZ/60 × 2
Since E2 = E1
8N2ΦZ/60 × 2 = 8N1ΦZ/60 × 8
N2 = N1 × 2/8 = 1000 × 2/8 = 250 rpm
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