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The subsequent type of first order differential equations which we'll be searching is correct differential equations. Before we find in the full details behind solving precise differential equations it's probably most excellent to work an illustration that will assist to demonstrate us just what an exact differential equation is. This will also demonstrate some of the behind the scenes details that we generally don't bother with in the solution process.
The huge majority of the subsequent example will not be done in any of the remaining illustrations and the work that we will place in the remaining illustrations will not be shown in this illustration. The whole point behind this illustration is to show you just what an accurate differential equation is, how we utilize this fact to arrive at a solution and why the process works like it does. The bulk of the actual solution details will be demonstrated in a later example.
If e were rational, then e = n/m for some positive integers m, n. So then 1/e = m/n. But the series expansion for 1/e is 1/e = 1 - 1/1! + 1/2! - 1/3! + ... Call the first n v
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Carry out the indicated operation and dropped down the answer to lowest terms. (x 2 - 5x -14/ x 2 -3x+2) . (x 2 - 4)/x 2 -14x+49) Solution This is a multiplication.
Let a = 5200 and b = 1320. (a) If a is the dividend and b is the divisor, determine the quotient q and remainder r. (b) Use the Euclidean Algorithm to find gcd(a; b). (c)
1) find the maxima and minima of f(x,y,z) = 2x + y -3z subject to the constraint 2x^2+y^2+2z^2=1 2)compute the work done by the force field F(x,y,z) = x^2I + y j +y k in moving
Graph f ( x ) = e x and g ( x ) = e - x . Solution There actually isn't a lot to this problem other than ensuring that both of these exponentials are graphed somewhere.
if 1/x+2, 1/x+3, 1/x+5 are in AP find x Ans 1/x+2,1/x+3, 1/x+5 are in AP find x. 1/x+3 - 1/x+2 = 1/x+5-1/x+3 => 1/x 2 +5x+6 = 2/ x 2 +8x +15 => On solving we get x
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The Limit : In the earlier section we looked at some problems & in both problems we had a function (slope in the tangent problem case & average rate of change in the rate of chan
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