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Evaluate stress induced in rod:
The two copper rods and one steel rod lie in vertical plane and support load of 50kN together as shown in figure given below. Each rod is 25 mm in diameter, the length of steel rod is 3 m and the length of each copper rod is 2m. If modulus of elasticity of steel is double that of copper, make calculations for stress induced in each rod. It can be presumed that each rod deforms by same amount. Sol.: Each rod deforms by same amount and accordingly that is,
Division of load between steel and copper rods is given below: total load = load carried by steel rod + rod carried by two copper rods
σC = (50 × 103)/1633.78 = 30.60 N/mm2 .......ANS σS = 1.33 C =1.33 × 30.60 = 40.7 N/mm2
Find the Machine Torque Angle (a) What are the four operating conditions that must be satisfied before a synchronous machine can be synchronised to an electrical grid? (b)
1. A hydraulic pump generates 240W and supplies hydraulic fluid at a rate of 5.1l/min to a linear actuator which has a bore size of 50 mm and a double piston rod diameter of 20mm.
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Q. Show Hazards associated with plants? Hazards associated with plants will typically include the following: • Inherent fire hazards presented by the release of flammable g
Airlines like to overbook their flights (this is a vibrant area of research called yield management). It is estimated that 10% of the people who book their flight do not show up. H
what are the necessity of lubrication ?
Find modulus of elasticity of the composite under isostrain: A composite is made of alternate layers of 60% E-glass and 40% epoxy resin. If modulii of elasticity of E-glass an
Fluid Friction: Fluid friction manifests when the lubricating fluid is introduced between contact surfaces of the two bodies. If thickness of lubricant or oil between the m
explain ways of representing alternative quantities;1)phasor representation 2)graphical representation 3)complex waves 4)addition and subtraction of sine wave
# how to calculate governor effort
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