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Evaluate stress induced in rod:
The two copper rods and one steel rod lie in vertical plane and support load of 50kN together as shown in figure given below. Each rod is 25 mm in diameter, the length of steel rod is 3 m and the length of each copper rod is 2m. If modulus of elasticity of steel is double that of copper, make calculations for stress induced in each rod. It can be presumed that each rod deforms by same amount. Sol.: Each rod deforms by same amount and accordingly that is,
Division of load between steel and copper rods is given below: total load = load carried by steel rod + rod carried by two copper rods
σC = (50 × 103)/1633.78 = 30.60 N/mm2 .......ANS σS = 1.33 C =1.33 × 30.60 = 40.7 N/mm2
A truss of 12 m span is loaded as shown in figure below. Determine the forces in the members of the truss by method of sections.
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Compression Ratio (r): It is the ratio of the total cylinder volume when the piston is at the bottom dead centre, V t to the clearance volume, V C . R= v t /v c
Step s Involved for Method of Section: The different steps involved are stated below: (1) First find out support reaction by using equilibrium conditions. (2) The truss
Separator: Separator works as insulator between positive and negative plates. These separators are placed between each pair of plates.
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