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Evaluate stress induced in rod:
The two copper rods and one steel rod lie in vertical plane and support load of 50kN together as shown in figure given below. Each rod is 25 mm in diameter, the length of steel rod is 3 m and the length of each copper rod is 2m. If modulus of elasticity of steel is double that of copper, make calculations for stress induced in each rod. It can be presumed that each rod deforms by same amount. Sol.: Each rod deforms by same amount and accordingly that is,
Division of load between steel and copper rods is given below: total load = load carried by steel rod + rod carried by two copper rods
σC = (50 × 103)/1633.78 = 30.60 N/mm2 .......ANS σS = 1.33 C =1.33 × 30.60 = 40.7 N/mm2
Determine the horizontal component of the force: A force of 80 N is working on a bolt as illustrated in Figure. Determine the horizontal and vertical components of the force.
Determine- cutting speed, Material removal rate and Machining time. A 150 mm long 12.7 mm diameter stainless steel rod is being turned to 12.19 mm diameter on a centre lathe.
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what is fluid statics ?
Forces working on dam: Let a dam retaining water as illustrated in Figure (a). What are the forces working on it? Solution The forces working on dam are as follows:
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