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Evaluate following limits.
Solution
In this case we also contain a 0/0 indeterminate form and if we were actually good at factoring we could factor the numerator & denominator, simplify and take the limit. Though, that's going to be more work than just utilizing L'Hospital's Rule.
L'Hospital's Rule works greatly on the two indeterminate forms 0/0 and ± ∞ /± ∞ . Though, there are several more indeterminate forms out there as we illustrated earlier. Let's see some of those and see how we can deal with those types of indeterminate forms.
We'll begin with the indeterminate form (0) ( ± ∞ ) .
4 1/2 ----2----1/3=3
A jeweler has bars of 18-carat gold and 12-carat gold. How much of every melted together to obtain a bar of 16-carat gold, weighing 120 gm ? It is given that pure gold is 24 carat.
solving
It is totally possible that a or b could be zero and thus in 16 i the real part is zero. While the real part is zero we frequently will call the complex numbers a purely imaginar
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Find the area enclosed between two concentric circles of radii 3.5cm, 7cm. A third concentric circle is drawn outside the 7cm circle so that the area enclosed between it and the 7
y=f(a^x) and f(sinx)=lnx find dy/dx Solution) dy/dx = (a^x)(lnx)f''(a^x), .........(1) but f(sinx) = lnx implies f(x) = ln(arcsinx) hence f''(x) = (1/arcsinx) (1/ ( ( 1-x
2/5x + x+1/3x
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