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Evaluate following limits.
Solution
In this case we also contain a 0/0 indeterminate form and if we were actually good at factoring we could factor the numerator & denominator, simplify and take the limit. Though, that's going to be more work than just utilizing L'Hospital's Rule.
L'Hospital's Rule works greatly on the two indeterminate forms 0/0 and ± ∞ /± ∞ . Though, there are several more indeterminate forms out there as we illustrated earlier. Let's see some of those and see how we can deal with those types of indeterminate forms.
We'll begin with the indeterminate form (0) ( ± ∞ ) .
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∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + c Detailed derivation of ∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx = ∫(cosec 2 x
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