Estimation of difference among two means
We know that the standard error of a sample is given by the value of the standard deviation (σ) divided by the square root of the number of items in the sample (√n).
However, when given two samples, the standard errors is described by
![885_Estimation of difference among two means.png](https://www.expertsmind.com/CMSImages/885_Estimation of difference among two means.png)
Also note that we do calculate approximately the interval not from the mean although from the difference between the two samples means that is: (x¯A - x¯B)
The appropriate number of confidence level does not change
Thus the confidence interval is described by:
(x¯A - x¯B) ± Confidence level S(x¯A - x¯B)
= (x¯A - x¯B) ± Z S(x¯A - x¯B)
Illustration
Given two samples A and B of 100 and 400 items respectively, they contain the means x¯1= 7 ad x¯2 = 10 and standard deviations of 2 and 3 respectively. Construct confidence interval at 70 percent confidence level?
Solution
Sample A B
x¯1 = 7 x¯2= 10
n1 = 100 n2 = 400
S1 = 2 S2 = 3
The standard error of the samples A and B is described by:
S(x¯A - x¯B) = √{(4/100) + (9/400)}
= ¼ = 0.25
At 70 percent confidence level, then appropriate number is equal to 1.04 or as read from the normal tables
(x¯1 - x¯2)= 7 - 10 = - 3 = 3
We take the absolute value of the difference among the means for illustration, the value of x¯ = absolute value of X that is a positive value of X.
Therefore Confidence interval is described by:
= 3± 1.04 (0.25 ) From the normal tables a z value of 1.04 provide a value of 0.7.
= 3± 0.26
= 3.26 and 2.974
Hence 2.974 ≤ X ≤ 3.26