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let x,y,z be the complex number such that x+y+z=2,x^2+y^2+z^=3,x*y*z=4,then 1/(x*y+z-1)+1/(x*z+y-1)+1/(y*z+x-1) is
The difference of two numbers is 18. The larger number is four more than twice the smaller. What are the numbers?
Now, let's solve out some double inequalities. The procedure here is alike in some ways to solving single inequalities and still very different in other ways. As there are two ineq
10 to the 50th exponent
3_-1 x+2 --- 1+_2 x+2
2. ABCD was a square sheet of paper, 6 cm on a side. As shown, corner D was folded to point F on the diagonal BD. The area of triangle EFG equals the area of the shaded L-shaped po
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Find g(f(h(-3))). f(x) = 2x -- g(x) = -3x+4 -- h(x) = -2x-8
I do not know how to do this
Solve following equations. 1/(x+1) = 1- (5/2x - 4) Solution Just like along with the linear equations the primary thing which we're going to
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