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Find amplitude of electric field ina parallel beam of light of intensity 2W/m2Ans:Given that intensity I=power/area=2W/M2by using this formula :intensity I=(Emax^2/2c mue not)from that Emax=magnitude of electric fieldc=velocity of light=3*10^8m/secmue not =4pi*10^-7Emax=38.82 N/m
Total height of the gymnast just before falling back down is=(2+.3)=2.3m Energy gained at that point = m*g*h(m=mass, g=gravitational force, h=height) =55*9.8*2.3=1239.7 J
The Szilard-Chalmers Reaction
Some phenomenon based on scattering: (i) Sky looks blue because of scattering. (ii) At the starting time of sunrise or sunset sun looks reddish. (iii) Danger signals are
Ergosphere The region about a rotating black hole, among the event horizon & the static limit, where rotational energy can be extracted through black hole.
numerical example
What are the applications of transmission electron microscope? Applications of the transmission electron microscope (TEM) a. The TEM is used into both material metallurgy, s
what are the advantages of using the thermo-electric thermometer over the mecury glass thermometer?
Q. State Huygen's principle. Huygen's principle: (a) Every point on a specified wave front may be considered as a source of secondary wavelets which spread out with the sp
how psuedo force is valid?
A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refr
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