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Find amplitude of electric field ina parallel beam of light of intensity 2W/m2Ans:Given that intensity I=power/area=2W/M2by using this formula :intensity I=(Emax^2/2c mue not)from that Emax=magnitude of electric fieldc=velocity of light=3*10^8m/secmue not =4pi*10^-7Emax=38.82 N/m
1 Coulumb Charges: 1 coulumb charge is that amount of charge which when placed 1 m from an identical charge in vacuum which repels it with a force of 8.99 × 109 N.
I WANT SHORT THEORY OF DEFLECTION MANGNETOMETER TAN A& TAN B
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