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Find amplitude of electric field ina parallel beam of light of intensity 2W/m2Ans:Given that intensity I=power/area=2W/M2by using this formula :intensity I=(Emax^2/2c mue not)from that Emax=magnitude of electric fieldc=velocity of light=3*10^8m/secmue not =4pi*10^-7Emax=38.82 N/m
why sky is blue?
100 =6=4=9=7=9
WORK AND ENERGY 1. Work can be defined as: the force applied in direction of displacement ×. This means that if the force F acts at an angle θ with respect to the direct
when a soft iron piece is buried under the surface of earth in the north south direction why the iron piece show properties of a magnet
Measuring with a Micrometer Caliper A simple animation of using a micrometer to measure the width of a pencil.
What are ferrites? Ferrites are ceramic compounds having trivalent metal having three valence electrons, iron and oxide of divalent element
Evaluate the speed will the string break A certain string just breaks when it is under400N of tension. A boy uses this string to whirl a 10-kgstone in a horizontal circle of rad
i. Open System - Here the system boundary is like energy and matter can enter or leave the system freely. Infect the system boundary here is imaginary. ii.Closed System - Here t
Flemings right hand rule: When a straight wire is moved through a magnetic field, an emf is induced in it, in the manner of the coil and magnet experiment. Once again, li
The mass of an automobile is 1140kg, and the distance between its front and rear axles is2.48 m. The center of gravity of theca is between the front and rear tires, and the horizon
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