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Find amplitude of electric field ina parallel beam of light of intensity 2W/m2Ans:Given that intensity I=power/area=2W/M2by using this formula :intensity I=(Emax^2/2c mue not)from that Emax=magnitude of electric fieldc=velocity of light=3*10^8m/secmue not =4pi*10^-7Emax=38.82 N/m
A boat travels 75 km southeast, then 56 km due east, then 25 km 30.0° north of east. a. Sketch the vector set on a N-E-S-W grid b. Find its net E-W part of displacement and
Electromotive force EMF (ξ) - This is the electrical energy from an ideal battery with no internal resistance. It is also the open circuit value of a battery (no current is drawn
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What is meant by tunnelling phenomenon? A tunnel diode is a high conductivity two-terminal P-N junction doped heavily about 1,000 times higher than a conventional junction diod
Adding 2 Vectors An easy demonstration of adding 2 vectors graphically. Also demonstrates in which vector addition is commutative.
FIND current using kvl
Described the two fundamental purpose of surveying?
Example 1:How far in meters does light travel in one year? Solution: 299,792,458m x 31,557,600s =9.461 x 10 to the power of15 Question, while i understand the above, why can we
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